Chapter 10: Problem 55
Write each equation in standard form, if it is not already so, and graph it. The problems include equations that describe circles, parabolas, ellipses, and hyperbolas. $$ y=-x^{2}+6 x-4 $$
Short Answer
Expert verified
The parabola is in standard form: \(y = -(x-3)^2 + 5\), and it opens downward with a vertex at (3,5).
Step by step solution
01
Identify the Type of Conic Section
The equation given is in the form of a quadratic equation in terms of variable \( y \): \[y = -x^2 + 6x - 4\]This is the equation of a parabola since it can be expressed in the form \( y = ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants and \( a \) is not equal to zero.
02
Convert to Standard Form of a Parabola
The standard form of a parabola that opens up or down is \[y = a(x-h)^2 + k\]To convert the given equation to this form, we need to complete the square for the quadratic expression in \( x \).
03
Rearrange and Complete the Square
First, focus on the quadratic terms in \( x \): \[y = -(x^2 - 6x) - 4\]Factor out \(-1\) from the \( x \) terms, and complete the square:\(x^2 - 6x = (x-3)^2 - 9\).Insert this back into the equation:\[y = -((x-3)^2 - 9) - 4\]
04
Simplify the Equation
Distribute the \(-1\) and simplify:\[y = -(x-3)^2 + 9 - 4\]So, the equation simplifies to:\[y = -(x-3)^2 + 5\]This is now in the standard form \(y = a(x-h)^2 + k\), where \(a = -1\), \(h = 3\), and \(k = 5\).
05
Identify Key Features for Graphing
From the equation \( y = -(x-3)^2 + 5 \), determine the vertex and direction:- The vertex \((h, k) = (3, 5)\).- Since \( a = -1 \), the parabola opens downward.
06
Sketch the Graph
Plot the vertex at \((3, 5)\) on the coordinate plane. Since the parabola opens downward ( 19, we can plot additional points by selecting x-values around the vertex and calculating corresponding y-values, such as \(x = 2\) and \(x = 4\), then mirror them across the vertex.Draw a smooth curve through these points to complete the graph.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parabolas
Parabolas are beautiful, U-shaped curves that you might encounter often in math. They are one type of conic section, which is a shape you get when a plane intersects with a cone.
In the world of algebra and geometry, a parabola is typically defined in terms of its equation, most commonly seen as a quadratic equation like \(y = ax^2 + bx + c\). This mathematical form allows us to identify the parabola's main features: the direction it opens (upward or downward if a vertical parabola), and its vertex, which is the highest or lowest point depending on the parabola's orientation.
The vertex represents an important characteristic of a parabola, giving us a point where the parabola "turns" and providing symmetry to its shape.
In the world of algebra and geometry, a parabola is typically defined in terms of its equation, most commonly seen as a quadratic equation like \(y = ax^2 + bx + c\). This mathematical form allows us to identify the parabola's main features: the direction it opens (upward or downward if a vertical parabola), and its vertex, which is the highest or lowest point depending on the parabola's orientation.
The vertex represents an important characteristic of a parabola, giving us a point where the parabola "turns" and providing symmetry to its shape.
- If the coefficient of \(x^2\), represented as \(a\), is positive, the parabola opens upwards, like a smile.
- On the other hand, if \(a\) is negative, it opens downward, like a frown.
Standard Form
The standard form of a parabola equation plays a crucial role in understanding its properties and graphing it effectively. The standard form for a vertical parabola is expressed as \(y = a(x-h)^2 + k\).
This form might look complex at first, but it's actually quite straightforward once you break it down:
This form might look complex at first, but it's actually quite straightforward once you break it down:
- \((h, k)\) is the vertex of the parabola. The vertex is that special point you need when sketching a parabola on a graph.
- The value of \(a\), just like in the general form, tells you whether the parabola opens up or down. A positive \(a\) means it opens up, while a negative \(a\) means it opens down.
Completing the Square
Completing the square is a powerful mathematical method used to convert a quadratic equation from general form to standard form. At its core, this technique transforms a quadratic expression \(x^2 + bx\) into a perfect square trinomial. But what does that mean? Let's break it down.
In general, if you have a quadratic term \(x^2 - 6x\), completing the square involves finding a value that, when added and subtracted, turns this expression into a perfect square. A perfect square is simply a quadratic expression that can be written as \( (x-d)^2 \).
Here's the step-by-step of completing the square:
In general, if you have a quadratic term \(x^2 - 6x\), completing the square involves finding a value that, when added and subtracted, turns this expression into a perfect square. A perfect square is simply a quadratic expression that can be written as \( (x-d)^2 \).
Here's the step-by-step of completing the square:
- Take half of the coefficient of \(x\), which is \(-6\). Half of this is \(-3\), and when squared, it equals \(9\).
- Rewrite the quadratic expression as \( (x-3)^2 - 9 \).
Graphing Conic Sections
Graphing conic sections, like parabolas, can initially seem daunting, but once you understand the steps, it becomes straightforward.
Here's a simple approach to sketching the graph of a parabola from its standard form:
Here's a simple approach to sketching the graph of a parabola from its standard form:
- Identify the vertex: Using the equation \(y = -(x-3)^2 + 5\), the vertex is \( (3, 5) \). This is the starting point of your graph.
- Determine the opening direction: The negative sign before the \(a\) value indicates the parabola opens downward.
- Plot additional points: Choose x-values around the vertex, calculate their corresponding y-values, and plot these on the graph. For instance, try \(x = 2\) and \(x = 4\). Because of the symmetry of parabolas, any point's mirror across the vertex can be used for further accuracy.
- Draw the curve: Connect these points with a smooth, U-shaped curve that opens downward. Be sure it passes through your vertex and plotted points accurately.