Chapter 8: Problem 70
Simplify the quotient, and write your answer in the form \(x^{r}\). $$ \frac{x^{\frac{1}{3}}}{x^{-\frac{1}{2}}} $$
Short Answer
Expert verified
The simplified quotient is \(x^{\frac{5}{6}}\).
Step by step solution
01
Apply the Quotient Rule for Exponents
Using the rule of exponents where \( \frac{a^m}{a^n} = a^{m-n} \), we can simplify the expression by subtracting the exponents.\[\frac{x^{\frac{1}{3}}}{x^{-\frac{1}{2}}} = x^{\frac{1}{3} - (-\frac{1}{2})}\]
02
Simplify the Exponent
Now, perform the subtraction within the exponent.\[\frac{1}{3} - \left( -\frac{1}{2} \right) = \frac{1}{3} + \frac{1}{2}\]Express \( \frac{1}{3} \) and \( \frac{1}{2} \) using a common denominator (6).\[\frac{1}{3} = \frac{2}{6} \quad \text{and} \quad \frac{1}{2} = \frac{3}{6}\]Adding these together:\[\frac{2}{6} + \frac{3}{6} = \frac{5}{6}\]
03
Final Expression
Now, substitute the simplified exponent back into the expression.\[x^{\frac{5}{6}}\]This is the simplified form of the original quotient.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quotient Rule for Exponents
The Quotient Rule for Exponents is a fundamental principle that helps us simplify expressions where the same base is divided with different exponents. When you see an expression like \( \frac{a^m}{a^n} \), it tells us to subtract the exponent in the denominator from the exponent in the numerator. This can be expressed as:
Consider the expression \( \frac{x^{\frac{1}{3}}}{x^{-\frac{1}{2}}} \). Apply the Quotient Rule by subtracting the exponent \(-\frac{1}{2}\) from \(\frac{1}{3}\). It is essential to remember that subtracting a negative number is equivalent to adding its positive value. Therefore:
- \( \frac{a^m}{a^n} = a^{m-n} \)
Consider the expression \( \frac{x^{\frac{1}{3}}}{x^{-\frac{1}{2}}} \). Apply the Quotient Rule by subtracting the exponent \(-\frac{1}{2}\) from \(\frac{1}{3}\). It is essential to remember that subtracting a negative number is equivalent to adding its positive value. Therefore:
- \( \frac{1}{3} - (-\frac{1}{2}) = \frac{1}{3} + \frac{1}{2} \)
Fractional Exponents
Fractional exponents can often be confusing at first sight, but a clear understanding can demystify these terms quickly. A fractional exponent, such as \( x^{\frac{1}{3}} \) or \( x^{-\frac{1}{2}} \), represents a radical expression. They denote both a power and a root, capturing two mathematical operations in a single notation.
The numerator of the fraction indicates the power, while the denominator conveys the root. For example:
The numerator of the fraction indicates the power, while the denominator conveys the root. For example:
- \( x^{\frac{1}{3}} \) means the cube root of \( x \) raised to the power of 1.
- \( x^{-\frac{1}{2}} \) implies the inverse (or reciprocal) of the square root of \( x \).
Simplifying Expressions
Simplifying expressions is an essential skill in algebra that leads to understanding and solving more complicated problems. The goal is to reduce an expression to its simplest form – a cleaner, more manageable version. This process often combines several mathematical principles and rules.
In our exercise example, simplifying the expression \( \frac{x^{\frac{1}{3}}}{x^{-\frac{1}{2}}} \) involved:
Finally, replacing \( 5/6 \) back into the expression simplifies it to \( x^{\frac{5}{6}} \), the simplest form that captures the essence of the original problem. Mastering simplification not only aids in problem-solving but also improves logical reasoning and analytical skills in mathematics.
In our exercise example, simplifying the expression \( \frac{x^{\frac{1}{3}}}{x^{-\frac{1}{2}}} \) involved:
- Using the Quotient Rule for Exponents to combine the powers.
- Handling fractional exponents by adjusting their terms.
- Finding a common denominator to perform arithmetic operations between fractions, like \( \frac{1}{3} \) and \( \frac{1}{2} \).
- \( \frac{1}{3} = \frac{2}{6} \)
- \( \frac{1}{2} = \frac{3}{6} \)
Finally, replacing \( 5/6 \) back into the expression simplifies it to \( x^{\frac{5}{6}} \), the simplest form that captures the essence of the original problem. Mastering simplification not only aids in problem-solving but also improves logical reasoning and analytical skills in mathematics.