Chapter 4: Problem 57
Find the roots of the given functions. \(f(x)=-2 x^{2}+7 x+4\)
Short Answer
Expert verified
The roots are \(x = -\frac{1}{2}\) and \(x = 4\).
Step by step solution
01
Identify the Standard Form
The quadratic function is given as \(f(x) = -2x^2 + 7x + 4\). This equation is already in the standard form of a quadratic equation, which is \(ax^2 + bx + c\), where \(a = -2\), \(b = 7\), and \(c = 4\).
02
Use the Quadratic Formula
The roots of a quadratic equation \(ax^2 + bx + c = 0\) can be found using the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]Here, substitute \(a = -2\), \(b = 7\), and \(c = 4\).
03
Calculate the Discriminant
Calculate the discriminant \(\Delta\) using the formula \(b^2 - 4ac\). Substitute the values to get:\[ \Delta = 7^2 - 4(-2)(4) \]\[ \Delta = 49 + 32 = 81 \]
04
Solve for the Roots
Since the discriminant is positive, there will be two distinct real roots. Use the quadratic formula:\[ x = \frac{-7 \pm \sqrt{81}}{-4} \]This simplifies to:\[ x = \frac{-7 \pm 9}{-4} \]Calculate for both roots:
05
Calculate the First Root
Using the positive square root:\[ x_1 = \frac{-7 + 9}{-4} = \frac{2}{-4} = -\frac{1}{2} \]
06
Calculate the Second Root
Using the negative square root:\[ x_2 = \frac{-7 - 9}{-4} = \frac{-16}{-4} = 4 \]
07
Write Final Answer
The roots of the function are \(x = -\frac{1}{2}\) and \(x = 4\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool used for finding the roots of any quadratic equation of the form \(ax^2 + bx + c = 0\). This is essential because it provides a solution even when the roots are not easily factorable. The formula is given by: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
Here's how it works:
Here's how it works:
- \(b\) is the coefficient of \(x\), \(a\) is the coefficient of \(x^2\), and \(c\) is the constant term.
- The \(\pm\) sign indicates there are potentially two solutions, one involving addition and the other involving subtraction.
- "\(\sqrt{b^2 - 4ac}\)" is called the discriminant, which we'll discuss more below.
Discriminant
The discriminant is a critical part of the quadratic formula, represented by \(b^2 - 4ac\). It helps determine the nature of the roots of the quadratic equation without actually solving it. Here's what the discriminant tells us:
- If \(\Delta > 0\), the quadratic equation has two distinct real roots. This means the parabola intersects the x-axis at two points.
- If \(\Delta = 0\), there is exactly one real root, often referred to as a repeated or double root. The parabola just touches the x-axis at one point (the vertex).
- If \(\Delta < 0\), there are no real roots. Instead, the roots are complex numbers, indicating that the parabola does not intersect the x-axis.
Real Roots
Real roots refer to the solutions of a quadratic equation that are real numbers. In the context of quadratic functions, these real roots represent the x-values where the parabola crosses the x-axis. Using the discriminant and the quadratic formula, we can mathematically predict and calculate these intersections.
In our example, since the discriminant is positive, we substitute \(\Delta = 81\) back into the quadratic formula:\[ x = \frac{-7 \pm \sqrt{81}}{-4} \] This becomes two separate calculations:
In our example, since the discriminant is positive, we substitute \(\Delta = 81\) back into the quadratic formula:\[ x = \frac{-7 \pm \sqrt{81}}{-4} \] This becomes two separate calculations:
- For the first root, use the positive square root: \(x_1 = \frac{-7 + 9}{-4} = -\frac{1}{2}\)
- For the second root, use the negative square root: \(x_2 = \frac{-7 - 9}{-4} = 4\)