Chapter 3: Problem 58
Set up a system of equations and use it to solve the following. A parabola passes through three points (?2,11), (?1,4) and (1,2). Use these points and to construct a system of three linear equations in terms of a, b, and c and solve it.
Short Answer
Expert verified
The equation of the parabola is \( y = 2x^2 - x + 1 \).
Step by step solution
01
Identify the General Form of a Parabola
A parabola can be expressed in the form \( y = ax^2 + bx + c \). The challenge is to find the coefficients \(a\), \(b\), and \(c\).
02
Substitute the First Point
Substitute the first point \((-2, 11)\) into the general equation, which results in the equation: \[ 11 = a(-2)^2 + b(-2) + c \]. This simplifies to \( 4a - 2b + c = 11 \).
03
Substitute the Second Point
For the second point \((-1, 4)\), substitute it into the equation: \[ 4 = a(-1)^2 + b(-1) + c \]. This simplifies to \( a - b + c = 4 \).
04
Substitute the Third Point
For the third point \((1, 2)\), substitute it into the equation:\[ 2 = a(1)^2 + b(1) + c \]. This simplifies to \( a + b + c = 2 \).
05
System of Equations
The system of equations formed is: 1. \( 4a - 2b + c = 11 \) 2. \( a - b + c = 4 \) 3. \( a + b + c = 2 \)
06
Solve the System of Equations - Eliminate c
Subtract the second equation from the third to eliminate \(c\):\( (a + b + c) - (a - b + c) = 2 - 4 \) which simplifies to \( 2b = -2 \), thus \( b = -1 \).
07
Substitute back to Solve for a and c
Now substitute \( b = -1 \) into the second equation: \( a - (-1) + c = 4 \) which simplifies to \( a + c = 3 \).Also substitute \( b = -1 \) into the first equation: \( 4a - 2(-1) + c = 11 \), simplifying to \( 4a + 2 + c = 11 \) thus \( 4a + c = 9 \).
08
Eliminate c Again and Solve for a
Subtract the equation \( a + c = 3 \) from \( 4a + c = 9 \) to eliminate \(c\):\( (4a + c) - (a + c) = 9 - 3 \) which simplifies to \( 3a = 6 \), thus \( a = 2 \).
09
Find c Using a
Substitute \( a = 2\) back into \( a + c = 3 \):\( 2 + c = 3 \), so \( c = 1 \).
10
Solution Summary
The coefficients are \( a = 2 \), \( b = -1 \), and \( c = 1 \). Thus, the equation of the parabola is \( y = 2x^2 - x + 1 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parabola Equation
A parabola is an important type of curve described by a quadratic equation in the form of \( y = ax^2 + bx + c \). This equation is central to many applications in mathematics and physics, giving us a way to describe and analyze parabolic shapes. The function depends on three coefficients: \( a \), \( b \), and \( c \). These coefficients determine the shape and position of the parabola:
- The coefficient \( a \) affects the direction and the "width" of the parabola. If \( a \) is positive, the parabola opens upwards; if negative, it opens downwards.
- The coefficient \( b \) influences the symmetry axis of the parabola, shifting it horizontally.
- The coefficient \( c \) represents the y-intercept, where the parabola crosses the y-axis.
Coefficients Determination
Determining the coefficients of a parabola requires using points that lie on the curve. Given several points of the parabola, you can substitute their coordinates into the quadratic equation \( y = ax^2 + bx + c \) to form a system of linear equations. For instance, substituting the point \((-2, 11)\) into the equation yields \( 11 = a(-2)^2 + b(-2) + c \), which simplifies to \( 4a - 2b + c = 11 \). Repeat this substitution process with other given points to form a set of equations:
- Each point provides a unique equation reflecting its position on the parabola.
- This process is repeated until a system of equations is created sufficient to solve for the unknown coefficients \(a\), \(b\), and \(c\).
Solving Linear Equations
Solving a system of linear equations is crucial in determining the coefficients of the parabola. Each equation corresponds to a point on the parabola, and the goal is to find \(a\), \(b\), and \(c\). The process begins by eliminating one variable at a time. For example, subtracting one equation from another can eliminate a variable, simplifying the equations to a form that is easier to solve. Let's look at the steps:
- Identify which variable can be eliminated easily and perform necessary operations between equations.
- After finding values for one or two variables, substitute back into other equations to determine the remaining values.