Chapter 2: Problem 61
Graph the linear function and label the \(x\) -intercept. $$f(x)=-5 x+15$$
Short Answer
Expert verified
The x-intercept is at (3, 0).
Step by step solution
01
Identify the function
The function given is a linear function: \( f(x) = -5x + 15 \). A linear function is usually in the form \( f(x) = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. Here, \( m = -5 \) and \( b = 15 \).
02
Find the x-intercept
To find the \( x \)-intercept, set \( f(x) = 0 \). Solve the equation for \( x \): \[0 = -5x + 15\]Add \(5x\) to both sides:\[5x = 15\]Divide by 5:\[x = 3\]Thus, the \( x \)-intercept is at \( (3, 0) \).
03
Find the y-intercept
The \( y \)-intercept occurs where \( x = 0 \). Substitute \( x = 0 \) into the function:\[f(0) = -5(0) + 15 = 15\]So, the \( y \)-intercept is at \( (0, 15) \).
04
Plot the intercepts
On a graph, plot the \( x \)-intercept at \( (3, 0) \) and the \( y \)-intercept at \( (0, 15) \). These points mark the intersection of the function with the \( x \)-axis and \( y \)-axis, respectively.
05
Draw the linear function
Using a ruler, draw a straight line through the points \( (3,0) \) and \( (0, 15) \). This line represents the graph of the linear function \( f(x) = -5x + 15 \).
06
Label the x-intercept
Clearly label the point \( (3, 0) \) on the graph as the \( x \)-intercept. This point is where the graph crosses the \( x \)-axis.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
x-intercept
The x-intercept of a function is the point where the graph of the function crosses the x-axis. In simpler terms, it's where the y-value equals zero. To find the x-intercept for a linear equation like the one we have here, which is given as: \[f(x) = -5x + 15\]You need to solve the equation for x when we set the function to zero:
- Set the function equal to zero: \[0 = -5x + 15\]
- Add 5x to each side to get: \[5x = 15\]
- Divide both sides by 5 to solve for x: \[x = 3\]
y-intercept
The y-intercept is another fundamental component of graphing linear equations. It's the point where the graph intersects the y-axis, meaning it happens when the x-value is zero. For the given linear function \[f(x) = -5x + 15\], we can easily find this point by:
- Substituting \(x = 0\) into the function: \[f(0) = -5(0) + 15\]
- This simplifies to: \[15\]
linear equations
Linear equations represent a straight line on a graph and are a foundational concept in algebra. A common form of a linear equation is the slope-intercept form, expressed as:\[y = mx + b\]Where \(m\) represents the slope, and \(b\) is the y-intercept. For our function:
- The equation is \(f(x) = -5x + 15\).
- Here, the slope \(m\) is -5.
- The y-intercept \(b\) is 15.