Chapter 9: Problem 363
(a) solve graphically and (b) write the solution in interval notation. $$x^{2}+6 x+5>0$$
Short Answer
Expert verified
The solution is \((-\infty, -5) \cup (-1, \infty)\).
Step by step solution
01
- Find the roots of the quadratic equation
To solve the inequality graphically, first find the roots of the quadratic equation by setting the inequality to zero: \[x^{2}+6x+5=0\]Solve using the quadratic formula \(x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\) where \(a=1\), \(b=6\), and \(c=5\).
02
- Calculate the roots
Plug the values into the quadratic formula:\[x = \frac{-6 \pm \sqrt{6^2-4(1)(5)}}{2(1)} = \frac{-6 \pm \sqrt{36-20}}{2} = \frac{-6 \pm \sqrt{16}}{2} = \frac{-6 \pm 4}{2}\]This gives the roots: \[x = -1 \text{ and } x = -5\].
03
- Sketch the parabola
The quadratic function \(x^2 + 6x + 5\) can be visualized as a parabola opening upwards (since the coefficient of \(x^2\) is positive). The roots \(x = -1\) and \(x = -5\) are the x-intercepts.
04
- Determine the intervals
To find the solution where \(x^2 + 6x + 5 > 0\), observe where the parabola is above the x-axis. The parabola is above the x-axis to the left of \(x = -5\) and to the right of \(x = -1\).
05
- Write the solution in interval notation
Combine the intervals from Step 4 to express the solution in interval notation. The solution is:\[(-\infty, -5) \cup (-1, \infty)\].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Solving Quadratic Equations
Understanding how to solve quadratic equations is a fundamental skill in algebra. A quadratic equation is typically written as \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants. The goal is to find the values of \(x\) that make the equation true.
- The most common method is the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2-4ac}}{2a} \). This formula is derived from the process of completing the square and works for any quadratic equation.
- You can also solve quadratic equations by factoring, where you express the quadratic as a product of its factors. However, this method only works easily when the equation factors neatly.
- Another way to solve is by graphing, which reveals the solutions as the points where the parabola intersects the x-axis, also known as the roots or zeros of the equation.
- Identify \(a = 1\), \(b = 6\), and \(c = 5\).
- Substitute these values into the formula: \(x = \frac{-6 \pm \sqrt{6^2-4(1)(5)}}{2(1)}\).
- Simplify under the square root: \(6^2 - 4(1)(5) = 36 - 20 = 16\).
- The roots are \(x = \frac{-6 + 4}{2} = -1\) and \(x = \frac{-6 - 4}{2} = -5\).
Graphing Parabolas
Graphing parabolas is another essential skill, especially when dealing with quadratic equations and inequalities. A parabola is the graph of a quadratic function, \(y = ax^2 + bx + c\). Understanding its key features can help you in solving various mathematical problems.
The roots, found previously as \(x = -1\) and \(x = -5\), indicate where the parabola crosses the x-axis.
By sketching the parabola, you can visualize these points and determine the regions where the quadratic inequality \(x^2 + 6x + 5 > 0\) holds true.
- The vertex is the highest or lowest point of the parabola, depending on whether it opens upwards (\(a > 0\)) or downwards (\(a < 0\)).
- The x-intercepts (or the roots) are the points where the parabola crosses the x-axis. These correspond to the solutions of the equation \(ax^2 + bx + c = 0\).
- The axis of symmetry is a vertical line that passes through the vertex, dividing the parabola into two mirror-image halves.
The roots, found previously as \(x = -1\) and \(x = -5\), indicate where the parabola crosses the x-axis.
By sketching the parabola, you can visualize these points and determine the regions where the quadratic inequality \(x^2 + 6x + 5 > 0\) holds true.
- The parabola is above the x-axis to the left of \(x = -5\).
- It also is above the x-axis to the right of \(x = -1\).
Interval Notation
Interval notation is a way of writing subsets of the real numbers in a concise, clear format. It is particularly useful when describing the solution sets of inequalities.
This translates to interval notation as: \((-\infty, -5) \cup (-1, \infty)\).
The union symbol (\(\cup\)) here means the combination of the two intervals.
Interval notation is an efficient way to express solutions for inequalities, setting the stage for more advanced mathematics.
- Around infinite endpoints, we use round brackets, like \((-\infty, a)\), to indicate that infinity is not a number you can reach.
- Closed intervals, indicating that endpoints are included, use square brackets like \([a, b]\).
- Open intervals, where endpoints are not included, use round brackets, such as \((a, b)\).
This translates to interval notation as: \((-\infty, -5) \cup (-1, \infty)\).
The union symbol (\(\cup\)) here means the combination of the two intervals.
Interval notation is an efficient way to express solutions for inequalities, setting the stage for more advanced mathematics.