Chapter 9: Problem 337
(a) rewrite each function in \(f(x)=a(x-h)^{2}+k\) form and (b) graph it by using transformations. $$f(x)=-x^{2}-4 x+2$$
Short Answer
Expert verified
The function in vertex form is \[f(x) = -(x + 2)^2 + 6\]. Plot the vertex at \((-2, 6)\) and apply the transformations.
Step by step solution
01
Identify the Original Form
The given function is \[f(x)=-x^{2}-4x+2.\]Identify it as a standard quadratic equation in the form \[f(x)=ax^2+bx+c.\]
02
Complete the Square
To rewrite the function in \(f(x) = a(x-h)^2 + k\) form, first complete the square. Rewrite \[-x^2 - 4x + 2\] as \[-(x^2 + 4x) + 2.\] Add and subtract the square of half the coefficient of\(x\): \[x^2 + 4x + 4 - 4 = (x + 2)^2 - 4.\]Thus, \[-(x^2 + 4x) = -( (x + 2)^2 - 4 ) = -(x + 2)^2 + 4.\] The function becomes \[f(x) = -(x + 2)^2 + 6.\]
03
Write the Vertex Form
The function is now in the vertex form: \[f(x) = -(x + 2)^2 + 6.\] Here, \(a = -1\), \(h = -2\), and \(k = 6.\)
04
Identify the Transformations
From the function \[f(x) = -(x + 2)^2 + 6\], identify the transformations:* Horizontal shift: left by 2 units.* Vertical shift: up by 6 units.* Reflection over the x-axis because \(a = -1\).
05
Plot the Graph
Start by plotting the vertex at \((-2, 6)\). Apply the horizontal shift left by 2 units and vertical shift up by 6 units. Reflect the parabola over the x-axis to show the function is opening downwards.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex Form
The **vertex form** of a quadratic function is a great way to understand the characteristics of the parabola represented by that function. The general form is \[f(x) = a(x-h)^2 + k\]. This form directly reveals the vertex of the parabola at the point \((h, k)\). Here are the key parts of the vertex form:
- \(a\): Determines the direction and width of the parabola. If \(a > 0\), the parabola opens upwards; if \(a < 0\), it opens downwards.
- \(h\): The horizontal shift from the origin. Positive values shift the graph to the right, and negative values shift it to the left.
- \(k\): The vertical shift from the origin. Positive values shift the graph up, and negative values shift it down.
Completing the Square
The process of **completing the square** is essential for rewriting a quadratic function from its standard form \(ax^2 + bx + c\) to the vertex form. This technique involves creating a perfect square trinomial inside the equation. Here’s how you can do it:1. **Factor the coefficient of \(x^2\):** If the coefficient is not 1, factor it out of the quadratic and linear terms.2. **Identify the term to complete the square:** Take the coefficient of \(x\), divide it by 2, and square it. This new term will create a perfect square trinomial.3. **Adjust the equation:** Add and subtract this new term within the parentheses. This keeps the equation balanced.4. **Rewrite the equation:** Combining the perfect square trinomial allows you to write the quadratic function in vertex form.Here’s a simple example for better understanding:
Given \(f(x) = -x^2 - 4x + 2\):
Given \(f(x) = -x^2 - 4x + 2\):
- Rewrite it to focus on the quadratic and linear terms: \[-(x^2 + 4x) + 2\].
- Complete the square: \[x^2 + 4x + 4 - 4\] which equals to \[(x + 2)^2 - 4\].
- Incorporate this into the equation: \[-(x + 2)^2 + 6\]. Now, the function is in its vertex form \(f(x) = - (x + 2)^2 + 6\).This method simplifies the graphing and transformation processes.
Graph Transformations
Graphing transformations for quadratic functions revolves around understanding how changes to the variables within the function affect the graph. Here’s a quick guide to the fundamental transformations:1. **Horizontal Shifts:** If the function is written as \(f(x) = a(x-h)^2 + k\), the \(h\) value will shift the graph left or right.
- Positive \(h\): Shift left by \(|h|\) units.
- Negative \(h\): Shift right by \(|h|\) units.
- Positive \(k\): Shift up by \(k\) units.
- Negative \(k\): Shift down by \(|k|\) units.
- \(a > 0\): Parabola opens upwards.
- \(a < 0\): Parabola opens downwards.
- **Start with the vertex:** Plot the vertex at \((-2, 6)\).
- **Apply transformations:** Shift left by 2 units and up by 6 units.
- **Reflect:** The negative \(a = -1\) indicates the parabola opens downwards.