Chapter 8: Problem 5
Simplify. (a) \(\sqrt{\frac{4}{9}}\) (b) \(-\sqrt{0.01}\)
Short Answer
Expert verified
(a) \( \frac{2}{3} \), (b) \( -0.1 \)
Step by step solution
01
Simplify the Fraction Inside the Square Root (a)
First, look at the fraction under the square root: \( \frac{4}{9} \). Both the numerator and the denominator are perfect squares. 4 is the square of 2, and 9 is the square of 3.
02
Take the Square Root of Each Part (a)
Take the square root of the numerator (4) and the square root of the denominator (9): \( \frac{\text{sqrt}(4)}{\text{sqrt}(9)} = \frac{2}{3} \).
03
Simplification Result (a)
Therefore, \( \text{sqrt}\bigg(\frac{4}{9}\bigg) = \frac{2}{3} \).
04
Recognize the Given Square Root (b)
For the second part, note that \( 0.01 \) can be recognized as a perfect square. \( 0.01 \) is actually \( 0.1^2 \).
05
Take the Square Root (b)
The square root of \( 0.01 \) is \( 0.1 \): \( \text{sqrt}(0.01) = 0.1 \).
06
Apply the Negative Sign (b)
Since the problem asks for the negative square root, we apply the negative sign: \( -\text{sqrt}(0.01) = -0.1 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
radicals
Radicals, represented by the square root symbol (√), are used to denote the square root of a number. The square root of a number is a value that, when multiplied by itself, gives the original number. For example, \(\text{sqrt}(16) = 4\), because \(4 \times 4 = 16\).
Understanding radicals helps in solving a variety of mathematical problems, including simplifying expressions and solving equations. When you see a fraction under a radical, you can simplify it by first simplifying the fraction and then taking the square root of the numerator and the denominator separately.
For example, in the problem \( \text{sqrt}\bigg(\frac{4}{9}\bigg)\), we notice both the numerator (4) and the denominator (9) are perfect squares. Therefore, we can simplify it to \(\frac{2}{3}\).
Understanding radicals helps in solving a variety of mathematical problems, including simplifying expressions and solving equations. When you see a fraction under a radical, you can simplify it by first simplifying the fraction and then taking the square root of the numerator and the denominator separately.
For example, in the problem \( \text{sqrt}\bigg(\frac{4}{9}\bigg)\), we notice both the numerator (4) and the denominator (9) are perfect squares. Therefore, we can simplify it to \(\frac{2}{3}\).
perfect squares
A perfect square is a number that is the square of an integer. In other words, it is a number that can be expressed as \( n^2 \) where \( n \) is an integer.
Examples of perfect squares include:
\( \text{sqrt}\bigg(\frac{4}{9}\bigg) = \frac{\text{sqrt}(4)}{\text{sqrt}(9)} = \frac{2}{3} \).
Examples of perfect squares include:
- 4 (since \(2^2 = 4\))
- 9 (since \(3^2 = 9\))
- 16 (since \(4^2 = 16\))
\( \text{sqrt}\bigg(\frac{4}{9}\bigg) = \frac{\text{sqrt}(4)}{\text{sqrt}(9)} = \frac{2}{3} \).
fraction simplification
Fraction simplification is the process of making a fraction as simple as possible. When dealing with radicals involving fractions, this simplification becomes very handy.
For example, if we have the fraction \( \frac{4}{9} \), we recognize that both the numerator (4) and the denominator (9) are perfect squares. We can rewrite the fraction under the radical as:
\( \text{sqrt}\bigg(\frac{4}{9}\bigg) = \frac{\text{sqrt}(4)}{\text{sqrt}(9)} = \frac{2}{3} \).
This result shows how useful simplification is. Instead of dealing with a more complex radical, we break it down into simpler, manageable parts.
For example, if we have the fraction \( \frac{4}{9} \), we recognize that both the numerator (4) and the denominator (9) are perfect squares. We can rewrite the fraction under the radical as:
\( \text{sqrt}\bigg(\frac{4}{9}\bigg) = \frac{\text{sqrt}(4)}{\text{sqrt}(9)} = \frac{2}{3} \).
This result shows how useful simplification is. Instead of dealing with a more complex radical, we break it down into simpler, manageable parts.
negative square root
A negative square root is simply the negative value of the principal (positive) square root. For instance, the principal square root of 4 is 2. Therefore, the negative square root of 4 is -2.
In the context of the given exercise, we are dealing with \-\text{sqrt}(0.01)\. Recognizing that \(0.01 = 0.1^2\), we find that the positive square root of 0.01 is 0.1:
\(\text{sqrt}(0.01) = 0.1\).
To apply the negative sign, we simply write:
\(-\text{sqrt}(0.01) = -0.1\).
It's important to remember that when a square root is negative, it means the final answer should carry the negative sign, just like in our example.
In the context of the given exercise, we are dealing with \-\text{sqrt}(0.01)\. Recognizing that \(0.01 = 0.1^2\), we find that the positive square root of 0.01 is 0.1:
\(\text{sqrt}(0.01) = 0.1\).
To apply the negative sign, we simply write:
\(-\text{sqrt}(0.01) = -0.1\).
It's important to remember that when a square root is negative, it means the final answer should carry the negative sign, just like in our example.