Chapter 6: Problem 270
Factor completely. $$ 16 x^{2}-24 x y+9 y^{2}-64 $$
Short Answer
Expert verified
(4x - 3y + 8)(4x - 3y - 8)
Step by step solution
01
- Recognize the quadratic expression
Observe that the given expression is a quadratic trinomial in terms of both x and y: \[ 16x^2 - 24xy + 9y^2 - 64 \]
02
- Group the terms
Group the quadratic and linear terms together and separate the constants: \[(16x^2 - 24xy + 9y^2) - 64 \]
03
- Factor the quadratic trinomial
Notice that \(16x^2 - 24xy + 9y^2\) is a perfect square trinomial. Factor it as: \[ (4x - 3y)^2 \]
04
- Rewrite the expression
Substitute the factored form back into the expression: \[ (4x - 3y)^2 - 64 \]
05
- Recognize the difference of squares
The expression \((4x - 3y)^2 - 64\) is a difference of squares. Use the formula \(a^2 - b^2 = (a + b)(a - b)\) to factor it: \[ (4x - 3y + 8)(4x - 3y - 8) \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Perfect Square Trinomial
Let's begin with understanding a perfect square trinomial. A perfect square trinomial takes the form of \(a^2 - 2ab + b^2\) or \(a^2 + 2ab + b^2\). These trinomials can be factored into \((a - b)^2\) or \((a + b)^2\) respectively. Notice how the given quadratic expression in the problem, \(16x^2 - 24xy + 9y^2 - 64\), includes the terms \(16x^2\), \(-24xy\), and \(9y^2\). These correspond to \(a^2\), \(-2ab\), and \(b^2\) respectively, where \(a = 4x\) and \(b = 3y\).
We recognize that:
We recognize that:
- \(16x^2\) is \((4x)^2\)
- \(9y^2\) is \((3y)^2\)
- \(-24xy\) is precisely \(-2 \cdot 4x \cdot 3y\)
Difference of Squares
Now, let's discuss the difference of squares. This is a common algebraic pattern where we have expressions like \(a^2 - b^2\), which can be factored into \((a + b)(a - b)\). In the given problem, after factoring the perfect square trinomial, we substitute and obtain \((4x - 3y)^2 - 64\).
Recognizing the term \(64\) as \(8^2\), we see that:
Recognizing the term \(64\) as \(8^2\), we see that:
- \( (4x - 3y)^2 \) is \(a^2\), where \(a = 4x - 3y\)
- \(64\) is \(b^2\), where \(b = 8\)
Grouping Terms
The concept of grouping terms is essential in factoring complex algebraic expressions. The idea is to reformat the expression in a way that highlights recognizable patterns. For the exercise at hand, we start with the quadratic expression \(16x^2 - 24xy + 9y^2 - 64\).
We observe and group terms as follows: \((16x^2 - 24xy + 9y^2) - 64\).
These steps illustrate the importance of recognizing patterns and strategically grouping terms to simplify and factor complex quadratic expressions.
We observe and group terms as follows: \((16x^2 - 24xy + 9y^2) - 64\).
- The terms \(16x^2 - 24xy + 9y^2\) form a recognizable pattern of a perfect square trinomial.
- The constant \(-64\) stands alone, aiding in subsequent factoring.
These steps illustrate the importance of recognizing patterns and strategically grouping terms to simplify and factor complex quadratic expressions.