Chapter 6: Problem 192
Factor completely using the difference of squares pattern, if possible. $$ p^{2}+14 p+49-q^{2} $$
Short Answer
Expert verified
(p + 7 - q)(p + 7 + q)
Step by step solution
01
Recognize the patterns
The given expression is: \[ p^{2} + 14p + 49 - q^{2} \] Notice that it contains a quadratic term in terms of \( p \) and a squared term in terms of \( q \). We can factor the quadratic part using the perfect square trinomial pattern.
02
Factor the perfect square trinomial
\[ p^{2} + 14p + 49 \] is a perfect square trinomial. It can be factored as: \[ (p + 7)^{2} \] because \( (p + 7)(p + 7) = p^{2} + 14p + 49 \)
03
Rewrite the expression
Substitute the factored form back into the original equation: \[ (p + 7)^{2} - q^{2} \]
04
Apply the difference of squares pattern
The expression \[ (p + 7)^{2} - q^{2} \] is a difference of squares, which factors as: \[ (A^2 - B^2 = (A - B)(A + B)) \] Here, \( A = p + 7 \) and \( B = q \), so: \[ (p + 7 - q)(p + 7 + q) \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Difference of squares
In algebra, the difference of squares is a special factoring pattern used to simplify expressions involving two squared terms. The pattern for the difference of squares states that \[ A^2 - B^2 = (A - B)(A + B) \]. This pattern is indispensable when simplifying certain quadratic expressions.For example, consider the expression we have \[ (p + 7)^2 - q^2 \]. Using the difference of squares pattern, we can set \[ A = p + 7 \] and \[ B = q \], giving us \[ (p + 7 - q)(p + 7 + q) \]. The main things to remember about the difference of squares are:
- It involves two terms.
- Both terms must be perfect squares.
- It is crucial for simplifying expressions involving subtracted squared terms.
Perfect square trinomial
A perfect square trinomial is a specific type of quadratic expression, which is the square of a binomial. The general form of a perfect square trinomial is \[ a^2 + 2ab + b^2 \], which factors into \[ (a + b)^2 \].Take \[ p^2 + 14p + 49 \] as an example from our original expression. This can be rewritten as \[ p^2 + 2 \times 7 \times p + 7^2 \],thus, we can factor it as \[ (p + 7)(p + 7) \] or \[ (p + 7)^2 \].Key points to recognize and factor perfect square trinomials include:
- A trinomial with a, 2ab, and b squared terms.
- The middle term is twice the product of the square roots of the first and last terms.
- It easily converts into a binomial square.
Quadratic expressions
Quadratic expressions are polynomials of degree 2, which means the highest exponent of the variable is 2. They usually have the general form \[ ax^2 + bx + c \], where a, b, and c are constants. Quadratic expressions appear frequently in various mathematical problems and must often be factored to find solutions.Factoring quadratics can take many approaches:
- Looking for patterns such as perfect square trinomials.
- Applying the difference of squares technique when applicable.
- Using methods like completing the square or the quadratic formula for more complex quadratics.