Chapter 4: Problem 219
In the following exercises, solve each system of equations using a matrix. $$ \left\\{\begin{array}{l} 2 x+5 y=4 \\ 3 y-z=3 \\ 4 x+3 z=-3 \end{array}\right. $$
Short Answer
Expert verified
Solve the system using matrix forms: inverse matrix multiplied by the constant matrix.
Step by step solution
01
Write the system in matrix form
First, rewrite the system of equations as a matrix equation of the form \(AX = B\). The given system is: \[ \begin{cases} 2x + 5y = 4 \ 3y - z = 3 \ 4x + 3z = -3 \end{cases} \] Write it in matrix form as \[ \begin{pmatrix} 2 & 5 & 0 \ 0 & 3 & -1 \ 4 & 0 & 3 \end{pmatrix} \begin{pmatrix} x \ y \ z \end{pmatrix} = \begin{pmatrix} 4 \ 3 \ -3 \end{pmatrix} \]
02
Find the inverse of matrix A
Calculate the inverse of the coefficient matrix A if it exists. The coefficient matrix is \[ A = \begin{pmatrix} 2 & 5 & 0 \ 0 & 3 & -1 \ 4 & 0 & 3 \end{pmatrix} \] Use Gaussian elimination or another method to find \( A^{-1} \). If \( A^{-1} \) exists, then \( X = A^{-1}B \).
03
Multiply A^{-1} by B
Multiply the inverse matrix \( A^{-1} \) by the constant matrix B to find the values of \( x, y, \text{and} z \). \[ X = A^{-1}B \]
04
Interpret the solution
The resulting matrix \( X \) will give the values of \( x, y, \text{and} z \). Compute the multiplication from the previous step to get these values.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Matrix Inversion
Matrix inversion is a pivotal concept when solving systems of linear equations using matrices. For a square matrix A, its inverse, denoted as \(A^{-1}\), satisfies the equation \(A \times A^{-1} = I\), where I is the identity matrix. The identity matrix is like the number 1 in regular multiplication; it doesn’t alter the matrix it’s multiplied with. Not all matrices have an inverse. A matrix must be square (same number of rows and columns) and have a non-zero determinant. To find the inverse, you can use Gaussian elimination, or formulas for smaller matrices like 2x2, where \(A^{-1} = \frac{1}{ad - bc} \begin{pmatrix} d & -b \ \ -c & a \end{pmatrix}\). For larger matrices, methods like Gaussian elimination or more advanced techniques involving row operations are used.
Gaussian Elimination
Gaussian elimination is a technique to solve systems of linear equations. It transforms the system’s matrix to a row-echelon form using row operations. These operations include swapping rows, multiplying rows by non-zero constants, and adding multiples of rows to others. The main goal is to simplify the matrix to easily solve for the variables. The process involves:
- Forming an augmented matrix by appending the constant matrix B to the coefficient matrix A.
- Using row operations to get zeros below the main diagonal.
- Achieving an upper triangular form from which back substitution can determine variable values.
Matrix Multiplication
Matrix multiplication involves combining two matrices to form a new one. For matrices A (of size m x n) and B (of size n x p), the product AB (of size m x p) is calculated by multiplying rows of A with columns of B and summing the products. Each element of the resulting matrix is:
- Take the row vector from matrix A.
- Take the column vector from matrix B.
- Multiply corresponding elements and sum them up.
Coefficient Matrix
The coefficient matrix represents the coefficients of variables in a system of linear equations. For the system:
\(\begin{cases} 2x + 5y = 4 \ 3y - z = 3 \ 4x + 3z = -3 \end{cases}\)
the coefficient matrix A is:
\(\begin{pmatrix} 2 & 5 & 0 \ 0 & 3 & -1 \ 4 & 0 & 3 \end{pmatrix}\).
This matrix is pivotal as it reflects how the variables interact with each other. When solving for unknowns, this matrix forms part of the matrix equation AX = B, where X contains the variables \(x, y, z \), and B contains constants on the right side of the equations.
\(\begin{cases} 2x + 5y = 4 \ 3y - z = 3 \ 4x + 3z = -3 \end{cases}\)
the coefficient matrix A is:
\(\begin{pmatrix} 2 & 5 & 0 \ 0 & 3 & -1 \ 4 & 0 & 3 \end{pmatrix}\).
This matrix is pivotal as it reflects how the variables interact with each other. When solving for unknowns, this matrix forms part of the matrix equation AX = B, where X contains the variables \(x, y, z \), and B contains constants on the right side of the equations.
Matrix Equation
A matrix equation is a way of representing systems of linear equations in matrix form. It is expressed as AX = B, where A is the coefficient matrix, X is the column matrix of variables, and B is the constant matrix. For the system of equations:
\(\begin{cases} 2x + 5y = 4 \ 3y - z = 3 \ 4x + 3z = -3 \end{cases}\)
The matrix equation form is:
\(\begin{pmatrix} 2 & 5 & 0 \ 0 & 3 & -1 \ 4 & 0 & 3 \end{pmatrix} \begin{pmatrix} x \ y \ z \end{pmatrix} = \begin{pmatrix} 4 \ 3 \ -3 \end{pmatrix} \).
Solving the matrix equation involves finding X, which can be done if the coefficient matrix A is invertible. If we find \(A^{-1}\), then \(X = A^{-1}B \).
\(\begin{cases} 2x + 5y = 4 \ 3y - z = 3 \ 4x + 3z = -3 \end{cases}\)
The matrix equation form is:
\(\begin{pmatrix} 2 & 5 & 0 \ 0 & 3 & -1 \ 4 & 0 & 3 \end{pmatrix} \begin{pmatrix} x \ y \ z \end{pmatrix} = \begin{pmatrix} 4 \ 3 \ -3 \end{pmatrix} \).
Solving the matrix equation involves finding X, which can be done if the coefficient matrix A is invertible. If we find \(A^{-1}\), then \(X = A^{-1}B \).