Chapter 11: Problem 60
(a) write the equation in standard form and (b) use properties of the standard form to graph the equation. $$ y=3 x^{2}-12 x+7 $$
Short Answer
Expert verified
Equation: \(3x^2 - 12x + 7\). Vertex: (2, -5). Opens upward.
Step by step solution
01
Write the Standard Form
The given equation is already a quadratic equation. To write it in the standard form, compare it with the standard form of a quadratic equation - which is - \(ax^2 + bx + c\), where \(a\), \(b\), and \(c\) are constants. In the given equation - y = 3x^2 - 12x + 7, we have: - - a = 3, b - = -12, and c = 7.
02
Identify the Vertex
For a quadratic function in the form \(ax^2 + bx + c\), the vertex (h, k) can be found using the formulas: - \( h = -\frac{b}{2a}\). Substituting the values of \(a\) and \(b\): - - h = -\frac{-12}{2 \times 3} = 2,- and - - k = y(2) = 3(2)^2 - 12(2) + 7 = -5.
03
Find the Axis of Symmetry
The axis of symmetry for a quadratic equation is the vertical line that passes through the vertex. Therefore, the line is \(x = h\). Substituting the value of \(h\), we get the axis of symmetry: - x = 2.
04
Determine the Direction of the Parabola
Since the coefficient of the \(x^2\) term (which is \(a\)) is positive, the graph of the quadratic equation will be a parabola that opens upward.
05
Find Additional Points to Graph the Parabola
To graph the parabola accurately, find additional points by plugging in \(x\) values into the original equation \(y = 3x^2 - 12x + 7\). For example, choose \(x = 0\) and \(x = 4\):- For \(x = 0\), \(y = 3(0)^2 - 12(0) + 7 = 7\).- For \(x = 4\), \(y = 3(4)^2 - 12(4) + 7 = 7\).
06
Plot the Vertex and Additional Points
Plot the vertex (2, -5), the axis of symmetry \(x = 2\), and the additional points (0, 7) and (4, 7) on the graph. Draw the parabola passing through these points.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Standard Form of a Quadratic Equation
The standard form of a quadratic equation is a foundational concept in algebra. It provides a way to express quadratic equations, making them easier to work with, especially when graphing. The standard form is$$y = ax^2 + bx + c$$ where \(a\), \(b\), and \(c\) are constants. In this form:
- \(a\) is the coefficient of \(x^2\)
- \(b\) is the coefficient of \(x\)
- \(c\) is the constant term
Vertex of a Parabola
In a quadratic equation, the vertex represents the highest or lowest point of the parabola. To find the vertex \((h, k)\), we use the formula: h = -b/(2a). Substituting in our values from the standard form,
- h = -(-12) / (2 * 3) = 2
Axis of Symmetry
The axis of symmetry is a vertical line that divides the parabola into two mirror-image halves. It passes through the vertex, making it quite straightforward to find. Using our \(h\) value from the vertex formula, the axis of symmetry is given by x = h. For our equation \(y = 3x^2 - 12x + 7\), since \(h = 2\), the axis of symmetry is
- x = 2
Direction of the Parabola
The direction of the parabola is determined by the sign of the coefficient \(a\) in the standard form. If \(a > 0\), the parabola opens upwards, and if \(a < 0\), it opens downwards. This affects the graph greatly as it tells us whether the vertex represents a minimum or maximum value. In our equation \(y = 3x^2 - 12x + 7\), the coefficient \(a = 3\), which is positive. Thus:
- The parabola opens upwards