Chapter 10: Problem 79
In the following exercises, graph each function in the same coordinate system. $$ f(x)=2^{x}, g(x)=2^{x-2} $$
Short Answer
Expert verified
Plot \( f(x) = 2^x \) and \( g(x) = 2^{x-2} \) on the same graph. \( g(x) \) is a horizontal shift of \( f(x) \).
Step by step solution
01
Understand the Functions
Identify the given functions and their forms: - Function 1: \( f(x) = 2^x \) - Function 2: \( g(x) = 2^{x-2} \)
02
Identify Key Points for f(x)
Determine key points to plot for \( f(x) = 2^x \) by choosing several values for \( x \): - \( x = -2, f(x) = 2^{-2} = \frac{1}{4} \) - \( x = -1, f(x) = 2^{-1} = \frac{1}{2} \) - \( x = 0, f(x) = 1 \) - \( x = 1, f(x) = 2 \) - \( x = 2, f(x) = 4 \)
03
Identify Key Points for g(x)
Determine key points to plot for \( g(x) = 2^{x-2} \) by choosing several values for \( x \): - \( x = -2, g(x) = 2^{-4} = \frac{1}{16} \) - \( x = -1, g(x) = 2^{-3} = \frac{1}{8} \) - \( x = 0, g(x) = 2^{-2} = \frac{1}{4} \) - \( x = 1, g(x) = 2^{-1} = \frac{1}{2} \) - \( x = 2, g(x) = 2^{0} = 1 \) - \( x = 3, g(x) = 2^{1} = 2 \) - \( x = 4, g(x) = 2^{2} = 4 \)
04
Plot the Points on the Coordinate System
Using the key points from Steps 2 and 3, plot \( f(x) = 2^x \) and \( g(x) = 2^{x-2} \) on the same coordinate system. Draw smooth curves through the points for each function.
05
Analyze the Graphs
Observe the transformations: - The graph of \( g(x) = 2^{x-2} \) is the graph of \( f(x) \) shifted 2 units to the right. - This reflects that \( g(x) \) represents a horizontal shift of \( f(x) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Function Transformation
Understanding function transformations is crucial when graphing exponential functions. A transformation alters the position or shape of the graph without changing the function's nature. For instance, in our equation set, we have:
- \( f(x) = 2^x \)
- \( g(x) = 2^{x-2} \)
- Vertical shifts
- Horizontal shifts
- Reflections
- Stretches and compressions
Key Points Plotting
Plotting key points is the backbone of graphing functions. To understand how an exponential function behaves, we calculate and plot a series of points.For \( f(x) = 2^x \), consider:
- \( x = -2, f(x) = 2^{-2} = \frac{1}{4} \)
- \( x = -1, f(x) = 2^{-1} = \frac{1}{2} \)
- \( x = 0, f(x) = 1 \)
- \( x = 1, f(x) = 2 \)
- \( x = 2, f(x) = 4 \)
- \( x = -2, g(x) = 2^{-4} = \frac{1}{16} \)
- \( x = -1, g(x) = 2^{-3} = \frac{1}{8} \)
- \( x = 0, g(x) = 2^{-2} = \frac{1}{4} \)
- \( x = 1, g(x) = 2^{-1} = \frac{1}{2} \)
- \( x = 2, g(x) = 2^{0} = 1 \)
- \( x = 3, g(x) = 2^{1} = 2 \)
- \( x = 4, g(x) = 2^{2} = 4 \)
Horizontal Shift
A horizontal shift changes the position of a function's graph along the x-axis. To understand better, examine our functions \( f(x) = 2^x \) and \( g(x) = 2^{x-2} \).The function \( g(x) \) stems from \( f(x) \), but with a shift. This horizontal shift can be seen in the term \( x-2 \), which implies a shift of 2 units to the right.
- If the shift had been \( x+2 \), the graph would move 2 units left.
- The horizontal shift does not alter the function's shape, only its position.
Exponential Growth
Exponential growth describes a rapid increase, where the rate of growth is proportional to the current value. In our example, both functions exhibit exponential growth.
- \( f(x) = 2^x \) starts slow, quickly escalating as x increases.
- \( g(x) = 2^{x-2} \) follows the same pattern but shifted horizontally.
- Rapid growth after initial stages
- Never touch the x-axis but approach it (asymptotic behavior)
- Growth determined by the base (2 in our case)