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91Ó°ÊÓ

Find an equation of the line that satisfies the given conditions. (a) Write the equation in slope-intercept form. (b) Write the equation in standard form. Through \((7,2) ;\) parallel to \(3 x-y=8\)

Short Answer

Expert verified
Slope-intercept form: y = 3x - 19. Standard form: 3x - y = 19.

Step by step solution

01

Identify the slope of the given line

The given line equation is in the form of standard form, which is: 3x - y = 8. To find the slope, convert it to slope-intercept form: y = mx + b. Let's solve for y:-y = -3x + 8.Multiply by -1:y = 3x - 8. So, the slope (m) is 3.
02

Use point-slope form for the new line

The point-slope form of a line is given by: y - y_1 = m(x - x_1).We have the point (7, 2) and the slope m = 3. Substitute these values into the formula: y - 2 = 3(x - 7).
03

Solve for y to convert to slope-intercept form

Expand and simplify the equation: y - 2 = 3x - 21.Add 2 to both sides: y = 3x - 19.So, the slope-intercept form is: y = 3x - 19.
04

Convert the slope-intercept form to standard form

Starting from the slope-intercept form: y = 3x - 19, let's convert it into the standard form (Ax + By = C):Move 3x to the left side: -3x + y = -19.Multiplying the entire equation by -1 to make the x term positive:3x - y = 19.So, the standard form is: 3x - y = 19.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

slope-intercept form
The slope-intercept form of a line equation is a convenient way to describe a line on a graph. It is written as:

\( y = mx + b \)

Key elements here are:
  • \( m \) represents the slope of the line, which shows how steep the line is.
  • \( b \) is the y-intercept, the point where the line crosses the y-axis.
To find the slope-intercept form from a standard equation like \( 3x - y = 8 \), you need to solve for \( y \). This was done by isolating \( y \) on one side:

\( y = 3x - 8 \).

So, the slope \( m \) is 3, and the y-intercept \( b \) is -8.
standard form
The standard form of a line equation is another common way to write the equation of a line. It is represented as:

\( Ax + By = C \)

Here:
  • \( A \) and \( B \) are coefficients of \( x \) and \( y \), respectively.
  • \( C \) is a constant.
  • \( A \) should not be negative, although different conventions may allow for it.
Converting from slope-intercept form to standard form involves rearranging the equation. Starting from \( y = 3x - 19 \), we move the \( 3x \) term by subtracting it from both sides to get:

\( -3x + y = -19 \).

Finally, we'll multiply the whole equation by \( -1 \) to make the \( x \) term positive, resulting in:

\( 3x - y = 19 \).
point-slope form
The point-slope form is especially useful for writing the equation of a line when you know a point on the line and the slope. It is expressed as:

\( y - y_1 = m(x - x_1) \)

Here:
  • \( m \) is the slope of the line.
  • (\( x_1 \), \( y_1 \)) is a specific point on the line.
In our exercise, the point given is (7, 2) and the slope \( m \) is 3. Plugging these values into the formula, we get:

\( y - 2 = 3(x - 7) \).

This form can then be rearranged to slope-intercept form by isolating \( y \).
parallel lines
Parallel lines have identical slopes but different y-intercepts. This means that while they never meet, they extend in the same direction.

In mathematical terms, if two lines are parallel, their slopes \( m_1 \) and \( m_2 \) are equal:

\( m_1 = m_2 \).

For the given problem, the initial line's equation is \( 3x - y = 8 \). Converting this to slope-intercept form, we found the slope as 3.

Any line parallel to this one must also have a slope of 3.

Hence, using the point (7, 2) and the slope 3 in point-slope form helps us write an equation for the new, parallel line.

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