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Find an equation of the line passing through the given points. (a) Write the equation in standard form. (b) Write the equation in slope-intercept form if possible. $$ \left(\frac{3}{4}, \frac{8}{3}\right) \text { and }\left(\frac{2}{5}, \frac{2}{3}\right) $$

Short Answer

Expert verified
Standard Form: \( 120x - 21y = 2 \)Slope-Intercept Form: \( y = \frac{40}{7}x - \frac{2}{21} \)

Step by step solution

01

Find the Slope

Use the formula for the slope of a line passing through two points: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] where \((x_1, y_1) = \left(\frac{3}{4}, \frac{8}{3}\right)\) and \((x_2, y_2) = \left(\frac{2}{5}, \frac{2}{3}\right)\). Substituting the values: \[ m = \frac{\frac{2}{3} - \frac{8}{3}}{\frac{2}{5} - \frac{3}{4}} = \frac{-\frac{6}{3}}{\frac{8}{20} - \frac{15}{20}} = \frac{-2}{-\frac{7}{20}} = \frac{40}{7} \] The slope is \( \frac{40}{7} \).
02

Use the Point-Slope Form

Use the point-slope formula of a line: \[ y - y_1 = m(x - x_1) \] With \(m = \frac{40}{7}\), \(x_1 = \frac{3}{4}\), and \(y_1 = \frac{8}{3}\), the equation becomes: \[ y - \frac{8}{3} = \frac{40}{7} \left( x - \frac{3}{4} \right) \]
03

Simplify the Equation to Slope-Intercept Form

Simplify and solve for \(y\). First distribute: \[ y - \frac{8}{3} = \frac{40}{7} x - \frac{30}{7} \] Add \( \frac{8}{3} \) to both sides: \[ y = \frac{40}{7} x - \frac{30}{7} + \frac{8}{3} \] Find a common denominator to combine the constants: \[ y = \frac{40}{7} x - \frac{30}{7} + \frac{56}{21} = \frac{40}{7} x - \frac{30}{7} + \frac{8}{3} \approx \frac{40}{7} x - \frac{30}{7} + \frac{168}{21} \approx \frac{40}{7} x + \frac{8}{3} \] Then combine and simplify: \[ y = \frac{40}{7} x - \frac{2}{21} \] The slope-intercept form is \( y = \frac{40}{7} x - \frac{2}{21} \).
04

Convert to Standard Form

Rewrite the slope-intercept form to standard form \( Ax + By = C \). Start from \( y = \frac{40}{7} x - \frac{2}{21} \): Multiply both sides by 21 to clear the fractions: \[ 21y = 120x - 2 \] Subtract \( 21y \) from both sides to get the standard form: \[ 120x - 21y = 2 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope
When finding the equation of a line, the first key concept is the slope. The slope measures how steep the line is and the direction it tilts. We calculate slope using the formula: \( m = \frac{y_2 - y_1}{x_2 - x_1} \). This formula uses the coordinates of two points on the line. In the given problem, the points are \( \left( \frac{3}{4}, \frac{8}{3} \right) \) and \( \left( \frac{2}{5}, \frac{2}{3} \right) \). By substituting these values into the formula, we get: \( m = \frac{\frac{2}{3} - \frac{8}{3}}{\frac{2}{5} - \frac{3}{4}} = \frac{-2}{-\frac{7}{20}} = \frac{40}{7} \). Note that the negative signs cancel each other out, giving us the slope \( \frac{40}{7} \). This slope tells us how much the line rises vertically for every unit it moves horizontally.
Point-Slope Form
After finding the slope, the next step is to use the point-slope form of the equation of a line. The point-slope form is expressed as: \( y - y_1 = m(x - x_1) \). It is particularly useful as it easily incorporates both a point on the line and the slope. Using our slope \( m = \frac{40}{7} \) and one of the points \( \left( \frac{3}{4}, \frac{8}{3} \right) \), we plug these values into the formula: \( y - \frac{8}{3} = \frac{40}{7} (x - \frac{3}{4}) \). This rearranges our line equation based on a specific point and the calculated slope, forming the foundation to convert to other line equation forms.
Slope-Intercept Form
The slope-intercept form is often the most intuitive and commonly used form for a line equation. It is written as \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. From the point-slope form \( y - \frac{8}{3} = \frac{40}{7} (x - \frac{3}{4}) \), we distribute and simplify to find \( b \). First, distribute the slope: \( y - \frac{8}{3} = \frac{40}{7} x - \frac{30}{7} \). Then add \( \frac{8}{3} \) to both sides. Finding a common denominator, we get: \( y = \frac{40}{7} x - \frac{30}{7} + \frac{56}{21} \). Simplifying gives: \( y = \frac{40}{7} x - \frac{2}{21} \). Here, \( \frac{40}{7} \) is the slope and \( -\frac{2}{21} \) is the y-intercept.
Standard Form
The standard form of a line equation is expressed as \( Ax + By = C \), where \( A \), \( B \), and \( C \) are integers, and \( A \) should be positive. To convert the slope-intercept form \( y = \frac{40}{7} x - \frac{2}{21} \) to standard form, we first eliminate the fractions by multiplying through by 21: \( 21y = 120x - 2 \). To align it into the standard structure, we rearrange terms to get \( 120x - 21y = 2 \). This equation now meets the standard form criteria.

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Most popular questions from this chapter

Segment PQ has the given coordinates for one endpoint P and for its midpoint M. Find the coordinates of the other endpoint \(Q .\) (Hint: Represent \(Q\) by \((x, y)\) and write two equations using the midpoint formula, one imolving \(x\) and the other involving \(y .\) Then solve for \(x\) and \(y .\) $$ P(2.5,1.75), M(3,2) $$

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