/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 Find the pH of the substance wit... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the pH of the substance with the given hydronium ion concentration. Ammonia, \(2.5 \times 10^{-12}\)

Short Answer

Expert verified
The pH of ammonia is approximately 11.60.

Step by step solution

01

Understand the pH Formula

The pH of a solution is calculated using the formula: \[ \text{pH} = -\text{log}[\text{H}_3\text{O}^+] \] where [\text{H}_3\text{O}^+] is the concentration of hydronium ions in moles per liter.
02

Identify Hydronium Ion Concentration

In this problem, the hydronium ion concentration is given as \[ [\text{H}_3\text{O}^+] = 2.5 \times 10^{-12} \] moles per liter.
03

Apply the pH Formula

Insert the hydronium ion concentration into the pH formula: \[ \text{pH} = -\text{log}(2.5 \times 10^{-12}) \]
04

Calculate the Logarithm

Use a calculator to find the logarithm: \[ \text{log}(2.5 \times 10^{-12}) \ = \text{log}(2.5) + \text{log}(10^{-12}) \ = 0.39794 - 12 \ = -11.60206 \]
05

Determine the pH

Insert the result from the logarithm into the pH formula: \[ \text{pH} = -(-11.60206) \ = 11.60206 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

hydronium ion concentration
Understanding hydronium ion concentration is key to grasping pH calculations. The concentration of hydronium ions \([\text{H}_3\text{O}^+]\) refers to the number of hydronium ions present in a unit volume of solution, typically measured in moles per liter (M). For example, in the given problem, the concentration is \(2.5 \times 10^{-12}\) M. This small number indicates that ammonia is a basic solution because it has a very low concentration of hydronium ions. Remember, the more hydronium ions present, the stronger the acidity of the solution. Conversely, fewer hydronium ions indicate a more basic (alkaline) solution.
logarithms in chemistry
Logarithms play a crucial role in chemistry, especially when dealing with exponential scales like pH. The pH formula uses the base-10 logarithm (log), which helps in transforming the small hydronium ion concentrations into manageable numbers. For the pH, the formula is: \[ \text{pH} = -\text{log}[\text{H}_3\text{O}^+] \] This means you take the logarithm of the hydronium ion concentration and then multiply it by -1. For instance, in the exercise when calculating \(\text{log}(2.5 \times 10^{-12})\), you split it into \( \text{log}(2.5) \) and \( \text{log}(10^{-12}) \), find their values separately, and add them together. This calculation simplifies interpreting the concentration into the pH value.
pH formula
The pH formula is a simple yet powerful tool in chemistry: \[ \text{pH} = -\text{log}[\text{H}_3\text{O}^+] \] This equation relates the acidity or basicity of a solution to its hydronium ion concentration. To use it:
  • Identify the hydronium ion concentration in moles per liter (M).
  • Insert this value into the logarithm function.
  • Multiply the result by -1.
For the given example with \(2.5 \times 10^{-12}\) M, we substitute into the formula: \[ \text{pH} = -\text{log}(2.5 \times 10^{-12}) \] After finding \( \text{log}(2.5) + \text{log}(10^{-12}) \), which is \(0.39794 - 12 \), we get \( -11.60206 \). Multiplying by -1 yields a pH of 11.60206, indicating a basic solution. Practicing these steps helps in efficiently and accurately determining the pH of various solutions.

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Most popular questions from this chapter

A major scientific periodical published an article in 1990 dealing with the problem of global warming. The article was accompanied by a graph that illustrated two possible scenarios. (a) The warming might be modeled by an exponential function of the form $$y=\left(1.046 \times 10^{-38}\right)\left(1.0444^{x}\right)$$ (b) The warming might be modeled by a linear function of the form $$y=0.009 x-17.67$$ In both cases, \(x\) represents the year, and y represents the increase in degrees Celsius due to the warming. Use these functions to approximate the increase in temperature for each of the following years. $$ 2040 $$

Sales (in thousands of units) of a new product are approximated by the function defined by $$ S(t)=100+30 \log _{3}(2 t+1) $$ where \(t\) is the number of years after the product is introduced. (a) What were the sales, to the nearest unit, after 1 yr? (b) What were the sales, to the nearest unit, after 13 yr? (c) Graph \(y=S(t)\)

To four decimal places, the values of \(\log _{10} 2\) and \(\log _{10} 9\) are $$ \log _{10} 2=0.3010 \quad \text { and } \quad \log _{10} 9=0.9542 $$ Evaluate each logarithm by applying the appropriate rule or rules from this section. $$ \log _{10} 162 $$

Use the properties of logarithms to write each expression as a single logarithm. Assume that all variables are defined in such a way that the variable expressions are positive, and bases are positive numbers not equal to 1. $$ 3 \log _{a} 5-\frac{1}{2} \log _{a} 9 $$

Use the properties of logarithms to write each expression as a single logarithm. Assume that all variables are defined in such a way that the variable expressions are positive, and bases are positive numbers not equal to 1. $$ \left(\log _{a} p-\log _{a} q\right)+2 \log _{a} r $$

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