Chapter 2: Problem 21
Show that the inequalities \(0.692 \leq \int_{0}^{1} x^{x} d x \leq 1\) are valid.
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Chapter 2: Problem 21
Show that the inequalities \(0.692 \leq \int_{0}^{1} x^{x} d x \leq 1\) are valid.
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\(\sqrt{1}+x\) Prove that, if \(\mathrm{n}>1\) (i) \(0<\int_{0}^{\pi / 2} \sin ^{n+1} x d x<\int_{0}^{\pi / 2} \sin ^{n} x d x\), (ii) \(0<\int_{0}^{\pi / 4} \tan ^{n+1} x d x<\int_{0}^{\pi / 4} \tan ^{n} x d x\). (iii) \(0.5<\int_{0}^{1 / 2} \frac{\mathrm{dx}}{\sqrt{\left(1-\mathrm{x}^{2 \mathrm{a}}\right)}}<0.524\).
Estimate \(\int_{0}^{3} \mathrm{f}(\mathrm{x}) \mathrm{d} x\) if \(\mathrm{it}\) is known that \(f(0)=10, f(0.5)=13, f(1)=14, f(1.5)=16, f(2)=18\) \(\mathrm{f}(2.5)=10, \mathrm{f}(3)=6 \mathrm{by}\) (a) the trapezoidal method. (b) Simpson's method.
Evaluate \(\int_{0}^{1}\left(\sqrt[3]{1-x^{7}}-\sqrt[7]{1-x^{3}}\right) d x\)
Find \(\int_{0}^{2} f(x) d x\), where
\(f(x)=\left\\{\begin{array}{c}\frac{1}{\sqrt[4]{x^{3}}} \quad \text { for } 0
\leq x \leq 1 \\ \frac{1}{\sqrt[4]{(x-1)^{3}}}\end{array}\right.\) for \(1
Show that \(\int_{0}^{\infty} x^{2} e^{-x^{2}} d x=\frac{1}{2} \int_{0}^{\infty} e^{-x^{2}} d x\)
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