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Suppose you roll two dice: a 12 -sided die with faces numbered 1 to \(12,\) and an 8 -sided die with faces numbered 1 to \(8 .\) a. How many possible number pairs can you roll? b. What sum is most likely? What is the probability of this sum? c. Is an odd sum or an even sum more likely?

Short Answer

Expert verified
a. There are 96 possible number pairs. b. The most likely sum is 10 with a probability of approximately 9.4%. c. Even sums are more likely than odd sums.

Step by step solution

01

Calculate total possible number pairs

The total number of possible outcomes when rolling two dice is the product of the number of faces on each die. For a 12-sided die and an 8-sided die, this is: \[ 12 \times 8 = 96 \] Therefore, there are 96 possible number pairs.
02

Determine the most likely sum

To determine the most likely sum, note that the sum's probability depends on the number of combinations that produce that sum. The possible sums range from 2 (1+1) to 20 (12+8). Calculate the number of combinations for these sums, and identify the sum with the highest combinations.
03

Calculate combinations for each sum

List the sums and count the combinations: Sum 2: 1 combination Sum 3: 2 combinations Sum 4: 3 combinations Sum 5: 4 combinations Sum 6: 5 combinations Sum 7: 6 combinations Sum 8: 7 combinations Sum 9: 8 combinations Sum 10: 9 combinations Sum 11: 8 combinations Sum 12: 7 combinations Sum 13: 6 combinations Sum 14: 5 combinations Sum 15: 4 combinations Sum 16: 3 combinations Sum 17: 2 combinations Sum 18: 1 combination Sum 19: 0 combinations Sum 20: 1 combination From this list, the most combinations are for Sum 10, with 9 combinations.
04

Calculate the probability of the most likely sum

To find the probability of rolling the most likely sum (10):\[ \text{Probability} = \frac{\text{Number of Combinations for Sum 10}}{\text{Total Number of Pairs}} = \frac{9}{96} = \frac{3}{32} \approx 0.094 \] Thus, the probability of rolling a sum of 10 is approximately 0.094 (or 9.4%).
05

Compare the probability of odd vs. even sums

Determine the number of odd and even sums. Sums range from 2 to 20. Pairs: Even sums: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20Odd sums: 3, 5, 7, 9, 11, 13, 15, 17, 19 Count the combinations for even and odd sums and compare them to see if odd or even sums are more likely.
06

Calculate combinations for odd and even sums

From previous calculations, the total number of combinations for even and odd sums are:Even sums: 3 (sum 2) + 10 + 5 + 7 + 9 + 7 + 5 + 3 + 1 = 50Odd sums: 1 (sum 3) + 2 + 4 + 6 + 8 + 6 + 4 + 2 + 1 = 46Therefore, even sums have a higher number of combinations.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinations in Probability
When you roll two dice, each combination of numbers that can appear as a result is an important concept in probability. Suppose you are using a 12-sided die and an 8-sided die. The outcome of rolling these two dice can be represented as pairs. For example, one possible pair is (1,1), another is (1,2), and so on. To determine the total number of possible outcomes, you multiply the number of faces of the first die by the number of faces of the second die.
Therefore, for a 12-sided die and an 8-sided die, there are
\[12 \times 8 = 96\]
possible combinations. Combinations play a fundamental role in calculating probabilities because they show all the possible ways you can achieve a particular result.
Dice Probability
Dice probability involves calculating the likelihood of different outcomes when rolling dice. The traditional method includes enumerating all possible outcomes and then identifying favorable ones. For example, when determining the most probable sum of rolling a 12-sided and an 8-sided die, you enumerate the sums ranging from the smallest possible (1+1=2) to the largest (12+8=20).
Then, you count how many combinations can produce each sum. By doing so, you identify that the sum of 10 is the most likely, with 9 combinations producing that sum.
The probability of rolling a sum of 10 is:
\[ \text{Probability} = \frac{\text{Number of Combinations for Sum 10}}{\text{Total Number of Pairs}} = \frac{9}{96} = \frac{3}{32} \text{ or approximately 0.094} \].
Sum of Dice Rolls
The sum of dice rolls is an interesting aspect when dealing with probability. When rolling two dice, the smallest possible sum you can get is 2 (when both dice show 1) and the largest possible sum is 20 (when one die shows 12 and the other 8). The sum that appears most frequently is determined by the highest number of combinations producing that sum.
By enumerating the sums and their producing combinations:
* Sum 2: 1 combination
* Sum 3: 2 combinations
* Sum 4: 3 combinations
*…and so on.
This computation reveals that the sum of 10 is the most probable.
Understanding the frequency of sums helps in predicting the outcome better and aids in strategic decision-making in games involving dice.
Even and Odd Sums
Determining whether an odd or even sum is more likely can be intriguing. When analyzing the sums possible from rolling a 12-sided and 8-sided die, the sums range from 2 to 20. You then need to identify which are even and which are odd:
* Even sums: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20
* Odd sums: 3, 5, 7, 9, 11, 13, 15, 17, 19

By counting the combinations you learn that:
* Even combinations: 50
* Odd combinations: 46
This suggests that even sums have a slightly higher probability. The total number of combinations tells you that even sums are more likely to appear when rolling these two dice.

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Most popular questions from this chapter

Five seventh grade friends—Anya, Ben, Calvin, Dan, and Ezra— challenged five eighth grade friends—Vic, Wendi, Xavier, Yvonne, and Zac—to a backgammon tournament. They put the names of the seventh graders into one hat and the names of the eighth graders into another. To determine the two players for each match, they pulled one name from each hat. a. What is the size of the sample space in this situation? That is, how many different pairs of names are possible? Explain. b. What is the probability that the next match will involve Anya and either Xavier or Yvonne? c. What is the probability that the next pair drawn will not involve Calvin? d. Suppose all 10 names are put into one hat, and two are drawn at random. What is the probability that the pair will include one seventh grader and one eighth grader? Explain.

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