/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 50 Rewrite each expression as simpl... [FREE SOLUTION] | 91Ó°ÊÓ

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Rewrite each expression as simply as you can. $$\left(a^{m}\right)^{n} \cdot\left(b^{3}\right)^{0}$$

Short Answer

Expert verified
a^{mn}

Step by step solution

01

Apply the Power of a Power Rule

Use the power of a power rule which states that \((a^m)^n = a^{mn}\). Apply this rule to the term \( (a^{m})^{n} \). This gives us \((a^{m})^{n} = a^{mn}\).
02

Simplify the Zero Exponent

Recall that any number raised to the power of zero is equal to one. Therefore, \((b^3)^0 = 1\).
03

Multiply the Simplified Expressions

Now we have \(a^{mn} \times 1\). Multiplying any number by 1 leaves it unchanged, so the expression simplifies to just \(a^{mn}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Rule in Exponents
One of the key rules in working with exponents is the power rule. This rule is particularly helpful when you have an exponent raised to another exponent. The power rule states:\[ (a^m)^n = a^{mn} \]In simpler terms, you multiply the exponents when one is raised to another. For example, if you have a base 'a' raised to a power 'm', which is further raised to the power 'n', the result will be 'a' raised to the product of 'm' and 'n'.
In our original exercise:\[ (a^m)^n \]Using the power rule:\[ (a^m)^n = a^{mn} \]This step helps to simplify complex, nested exponents into a single term. Understanding this rule makes working with exponential expressions much more manageable.
Key points to remember:
  • Exponents are multiplied when using the power rule.
  • This rule helps simplify nested exponents.
  • It’s applicable to any base, not just numbers.
Zero Exponent Rule
Another crucial rule in algebra involving exponents is the zero exponent rule. It can be a game-changer when simplifying expressions. The zero exponent rule states:\[ b^0 = 1 \]This means any non-zero number or algebraic term raised to the power of zero is equal to one. This is super handy because it can turn a complicated-looking part of an expression into something simple.
In our problem, we have:\[ (b^3)^0 \]Using the zero exponent rule:\[ (b^3)^0 = 1 \]Why does this matter? It clears out parts of the expression that don’t contribute to the final value. The whole term collapses to 1, making our further calculations much easier.
Key takeaways:
  • Any non-zero base raised to zero is 1.
  • This rule simplifies parts of expressions instantly.
  • Always check for zero exponents to make the expression easier.
Simplification in Algebra
Simplifying algebraic expressions is a fundamental skill in mathematics. It involves breaking down expressions into their simplest form using various algebraic rules. Here are the steps to simplify effectively:
1. **Apply exponent rules**: Use rules like the power rule and zero exponent rule to simplify terms involving exponents.
2. **Combine like terms**: Group and combine terms that have the same variable raised to the same power.
3. **Perform operations**: Carry out any multiplications, divisions, additions, or subtractions as required.
In our current example, after simplifying individual components using the power rule and zero exponent rule, we get:\[ a^{mn} \times 1 \]Since multiplying by 1 doesn’t change the value, the final simplified expression is:\[ a^{mn} \]Mastering simplification trips is about practice and understanding fundamental rules. It turns complex expressions into something you can easily manage.
Key principles:
  • Use exponent rules as your first step.
  • Always combine like terms.
  • Don’t overlook simplification opportunities within the expression.
Understanding and practicing these steps will help you achieve clearer and more accurate algebraic work!

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Most popular questions from this chapter

Solve the systems of equations in Exercises \(8-11\) by elimination, and check your solutions. Give the following information: \(\cdot\) which variable you eliminated \(\cdot\) whether you added or subtracted equations \(\bullet\) the solution $$ \begin{array}{l}{9 s+2 t=3} \\ {4 s+2 t=8}\end{array} $$

Consider the inequality \(x^{3} \leq 27.\) a. Express the solution of \(x^{3} \leq 27\) as an inequality. b. Graph the solution on a number line.

Solve each equation by backtracking. (Backtrack mentally if you can.) Check your solutions. $$ 2(n-5)=7 $$

Recall that the absolute value of a number is its distance from 0 on the number line. You can solve equations involving absolute values. For example, the solutions of the equation \(|x|=8\) are the two numbers that are a distance of 8 from 0 on the number line, 8 and \(-8 .\) Solve each equation. $$ \begin{array}{ll}{\text { a. }|a|=2.5} & {\text { b. }|2 b+3|=8} \\ {\text { c. }|9-3 c|=6} & {\text { d. } \frac{15 d 1}{25}=1} \\ {\text { e. }|-3 e|=15} & {\text { f. } 20+|2.5 f|=80}\end{array} $$

Economics A manager of a rock group wants to estimate, based on past experience, how many tickets will be sold in advance of the next concert and how many tickets will be sold at the door on the night of the concert. At a recent concert, the \(1,000\) -seat hall was full. Tickets bought in advance cost \(\$ 30\) , tickets sold at the door cost \(\$ 40\) , and total ticket sales were \(\$ 38,000\) . a. Write a system of two equations to represent this information. b. On one set of axes, draw graphs for the equations. c. Use your graphs to estimate the number of advance sales and the number of door sales made that night. d. Check that your estimates fit the conditions by substituting them into both equations.

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