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Solve the systems of equations in Exercises \(12-15\) by elimination, and check your solutions. Give the following information: \(\cdot\) which equation or equations you rewrote \(\cdot\) how you rewrote each equation \(\cdot\) whether you added or subtracted equations \(\cdot\) the solution $$ \begin{array}{ll}{y=\frac{3}{4} x-4} & {[\mathrm{G}]} \\ {4 y=2 x+3} & {[\mathrm{H}]}\end{array} $$

Short Answer

Expert verified
The solution is \( x = 19 \) and \( y = 10.25 \).

Step by step solution

01

Rewrite Equation G in standard form

The original equation is given as \( y = \frac{3}{4} x - 4 \). Multiply every term by 4 to eliminate the fraction: \( 4y = 3x - 16 \).
02

Rewrite Equation H in standard form

The original equation is given as \( 4y = 2x + 3 \). This equation is already in an appropriate form for elimination.
03

Subtract Equations

Subtract Equation H from the rewritten Equation G to eliminate the variable \( y \): \[\begin{aligned} &4y - 4y = 3x - 2x - 16 - 3 \ \implies & 0 = x - 19 \ \implies & x = 19 \ \end{aligned}\]Thus, \( x = 19 \).
04

Substitute \( x \) into one of the original equations

Substitute \( x = 19 \) into Equation G: \[ \begin{aligned} y &= \frac{3}{4} (19) - 4 \= \frac{57}{4} - 4 \= \frac{57}{4} - \frac{16}{4} \= \frac{41}{4} \= 10.25 \].Thus, \( y = 10.25 \).
05

Verify the solution

Substitute \( x = 19 \) and \( y = 10.25 \) into Equation H to verify: \[\begin{aligned} 4y &= 2x + 3 \ \implies& 4(10.25) = 2(19) + 3 \ \implies& 41 = 38 + 3 \ \implies& 41 = 41 \ \end{aligned} \].The solution satisfies Equation H.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Elimination Method
The Elimination Method is one of the techniques used to solve systems of equations. This method involves eliminating one variable by adding or subtracting the equations.

In our example, we had two equations:
\( y = \frac{3}{4} x - 4\) and \( 4 y = 2 x + 3 \).

First, we need to rewrite both equations in standard form. For the first equation, this means eliminating the fraction by multiplying every term by 4, transforming it from \( y = \frac{3}{4} x - 4 \) to \( 4 y = 3 x - 16 \). The second equation, \( 4 y = 2 x + 3 \), is already in standard form.

Next, we align the equations and subtract the second equation from the first to eliminate the variable \( y \). This gives us \( 0 = x - 19 \), leading to \( x = 19 \).

By eliminating one variable, we simplify the system and can easily solve for the remaining variable.
Substitution Method
The Substitution Method involves solving one equation for one variable and then substituting that solution into the other equation.

In this context, we first solve one of the equations for one of the variables. For example, equation G is solved for \( y \)
\( y = \frac{3}{4}x - 4 \).

We then substitute \( x = 19 \) from our elimination result into this equation:
\( y = \frac{3}{4}(19) - 4 \).
This step-by-step method allows us to find the value of \(y\) as 10.25.

Substitution is particularly useful when one variable's coefficient is 1 or -1 because it simplifies the calculations.
Standard Form
Equations in Standard Form are presented as \( Ax + By = C \), where \( A \), \( B \), and \( C \) are constants and \( x \) and \( y \) are variables.

Rewriting equations in standard form makes it easier to apply the elimination method.

For example, transforming equation G from \( y = \frac{3}{4} x - 4 \) to \( 4 y = 3 x - 16 \) puts both equations on equal terms. This step simplifies the elimination process.

Equations in standard form allow for systematic manipulations, creating consistency across different problems and methods.

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Most popular questions from this chapter

A rock climber launched a hook from the base of a cliff. The edge of the cliff is 100 feet above the climber. Use the formula for the height of a thrown object, \(h=v t-16 t^{2},\) to answer these questions. (Assume that the hook is thrown straight up and, if it travels high enough, catches the edge of the cliff during its descent.) a. Can the hook reach the top of the cliff if its initial velocity is 70 feet per second, or 70 fos? Explain. b. Find an initial velocity that would be sufficient to allow the hook to reach the cliff's edge. c. At an initial velocity of 100 fps, how far above the edge of the cliff will the hook rise? d. At an initial velocity of 100 fps, how long will it take until the hook catches the top of the cliff on its way back down?

A group of friends enters a restaurant. No table is large enough to seat the entire group, so the friends agree to sit at several separate tables. They want to sit in groups of \(5,\) but there aren't enough tables: 4 people wouldn't have a place to sit. Someone suggests they sit in groups of \(6,\) which would fill all the tables, with 2 extra seats at one table. Answer these questions to find how many people are in the group and how many tables are available. a. Write a system of two equations to describe the situation. b. Solve your system of equations. How many friends are in the group, and how many tables are available? Check your work.

List five values that satisfy each inequality. Include negative and positive values, if possible. $$6< x<7$$

Solve the systems of equations in Exercises \(12-15\) by elimination, and check your solutions. Give the following information: \(\cdot\) which equation or equations you rewrote \(\cdot\) how you rewrote each equation \(\cdot\) whether you added or subtracted equations \(\cdot\) the solution $$ \begin{array}{ll}{6 x+y=-54} & {[\mathrm{C}]} \\ {2 x-5 y=-50} & {[\mathrm{D}]}\end{array} $$

Solve each equation by backtracking. (Backtrack mentally if you can.) Check your solutions. $$ \frac{n}{2}+5=7 $$

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