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For Exercises 20–28, answer Parts a and b. a. What is the constant difference between the \(y\) values as the \(x\) values increase by 1\(?\) b. What is the constant difference between the \(y\) values as the \(x\) values decrease by 2\(?\) $$ y=3 x-3 $$

Short Answer

Expert verified
a. 3, b. -6

Step by step solution

01

Identify the slope

The given equation is in the form of a linear equation, which is written as \( y = mx + b \). In this equation, \( m \) represents the slope of the line. For the equation \( y = 3x - 3 \), the slope \( m \) is 3.
02

Constant difference as x increases by 1

When the x-values increase by 1, the change in \( y \)-values can be directly found from the slope. Since the slope \( m \) is 3, the constant difference between the \( y \)-values as the \( x \)-values increase by 1 is 3.
03

Calculate Δy for x decreasing by 2

To find the constant difference in \( y \)-values as the \( x \)-values decrease by 2, use the slope \( m \). For each unit decrease in \( x \), \( y \) decreases by 3. Therefore, when \( x \)-values decrease by 2, \( y \)-values decrease by \( 3 \times 2 = 6 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

slope
The slope of a linear equation is a crucial concept to understand. It indicates how steep a line is and the direction it’s going. In the equation given in the exercise, which is written as \( y = 3x - 3 \), the slope \( m \) is the coefficient of \( x \), which is 3. This means for every increase of 1 in \( x \), the \( y \)-value increases by 3. The slope can be positive, negative, or zero:
  • A positive slope means the line rises as it moves from left to right.
  • A negative slope means the line falls as it moves from left to right.
  • A zero slope means the line is flat.
In our case, the slope is 3, showing a line rising upward at a steady rate.
constant difference
The constant difference refers to the consistent change in the \( y \)-values when the \( x \)-values are adjusted by a fixed amount. It's directly tied to the slope in a linear equation. Here, the slope \( m = 3 \) tells us about the constant difference:
  • When \( x \) increases by 1, \( y \) increases by the slope amount, which is 3.
  • From the second part of the exercise, if \( x \) decreases by 2, the \( y \)-value changes by \( 3 \times (-2) = -6 \). Thus, the \( y \)-values decrease by 6.
The constant difference helps us quickly understand how the \( y \)-values react to changes in \( x \). This makes it easy to predict how the line moves.
y-values
In a linear equation like \( y = 3x - 3 \), the \( y \)-values are determined by the equation, based on the given \( x \)-values. The \( y \text{-values} \) depend on the slope and the starting point (or y-intercept). Let’s break it down:
1. Starting Point: When \( x = 0 \), we get the y-intercept by solving for \( y \text{-values} \): \( y = 3(0) - 3 = -3 \). So, the line crosses the y-axis at -3.
2. Using the Slope: When you know the slope and move along the \( x \)-axis, you can find the corresponding \( y \)-values. For example, if \( x \text{increased} \) by 1, \( y = 3(1) - 3 = 0 \). If \( x = -2 \), \( y = 3(-2) - 3 = -9 \).
By increasing or decreasing \( x \), keeping the slope in mind will tell you the exact behavior of the \( y \)-values.

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Most popular questions from this chapter

For Exercises 20–28, answer Parts a and b. a. What is the constant difference between the \(y\) values as the \(x\) values increase by 1\(?\) b. What is the constant difference between the \(y\) values as the \(x\) values decrease by 2\(?\) $$ y=x+2 $$

Find an equation of the line passing through the given points. $$ (3,4) \text { and }(7,8) $$

In Exercises \(8-11\) , you are given a slope and a point on a line. Find another point on the same line. Then draw the line on graph paper. $$ \frac{1}{4} ; \text { point }(4,5) $$

Three cellular telephone companies have different fee plans for local calls. i. Talk-It-Up offers a flat rate of \(\$ 50\) per month. You can talk as much as you want for no extra charge. i. One Thin Dime charges \(\$ 0.10\) for each half minute, with no flat rate. iii. CellBell charges \(\$ 30\) per month and then \(\$ 0.10\) per minute for all calls made. a. For each company, write an equation that relates the cost of the phone service, \(c\), to the number of minutes a customer talks during a month, \(t\). b. Any linear equation can be written in the form \(y=m x+b\) . Give the value of \(m\) and \(b\) for each equation you wrote in Part a. c. For each company, make a graph that relates the cost of the phone service to the number of minutes a customer talks during a month. d. Where do the values of \(m\) and \(b\) appear in the graph for each phone company?

If possible, write each equation in the form \(y=m x+b .\) Then identify the slope and the \(y\) -intercept. $$y-19=-2(x-3)$$

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