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For Exercises 20–28, answer Parts a and b. a. What is the constant difference between the \(y\) values as the \(x\) values increase by 1\(?\) b. What is the constant difference between the \(y\) values as the \(x\) values decrease by 2\(?\) $$y=x$$

Short Answer

Expert verified
a. 1; b. -2

Step by step solution

01

Understanding the Function

The given equation is a linear function: \[ y = x \] This means that for every 1 unit increase in x, y also increases by 1 unit.
02

(Part a): Evaluate the Constant Difference for Increase by 1

For part (a), we need to determine the difference in y-values as x increases by 1. Let's calculate the y-values for consecutive x-values: When x = 1, y = 1 When x = 2, y = 2 The difference between these y-values is: \[ 2 - 1 = 1 \] So, our constant difference is 1.
03

(Part b): Evaluate the Constant Difference for Decrease by 2

For part (b), we need to determine the difference in y-values as x decreases by 2. Let's calculate the y-values for x-values separated by 2 units: When x = 2, y = 2 When x = 0, y = 0 The difference between these y-values is: \[0 - 2 = -2\] So, our constant difference is -2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

constant difference
When dealing with linear functions, the concept of a constant difference is vital. This means that the difference between consecutive output values (y-values) remains constant as we change the input values (x-values) by the same amount. In our exercise, we considered the function y = x. For each increase of 1 in the x-value, the y-value also increases by 1, showing a constant difference of 1. Similarly, if the x-value decreases by 2, the y-value also decreases by 2. This invariant difference is the hallmark of linear functions and simplifies predicting future values.

This understanding helps form the basis for analyzing more complex functions or scenarios where such regular patterns exist.
x and y values
In the context of linear functions, the relationship between x and y values is straightforward. For our function, y = x, each x-value directly corresponds to a y-value. This means:

  • When x = 1, y = 1

  • When x = 2, y = 2

  • When x = 3, y = 3

The x-values and y-values increase at the same rate. To see this in action, consider making a table:
When x increases:

  • x = 1, y = 1

  • x = 2, y = 2 (Difference: 1)

When x decreases:

  • x = 2, y = 2

  • x = 0, y = 0 (Difference: -2)

Observing the values this way emphasizes how the constant difference translates to a predictable and linear pattern.
function evaluation
Function evaluation is about substituting values into the function to find corresponding output values. In our case, the linear function y = x makes it simple:

  • Choose a value for x, such as 1

  • Substitute it into the function to get y = 1

This straightforward relationship ensures that for every x-value, the corresponding y-value is easily determined. Evaluating a function involves:

  • Selecting x-values

  • Substituting these into the function

  • Calculating the resulting y-values

This process assists in creating tables and graphs to visually represent how x and y values are interconnected, supporting a deeper grasp of the linear function’s behavior.

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