Chapter 3: Problem 3
Show that \(\tan 5 x-\tan 2 x-\tan 3 x=\tan 2 x \tan 3 x \tan 5 x\)
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Chapter 3: Problem 3
Show that \(\tan 5 x-\tan 2 x-\tan 3 x=\tan 2 x \tan 3 x \tan 5 x\)
These are the key concepts you need to understand to accurately answer the question.
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$$ \text { Solve the equation: } \tan ^{-1}(2 \mathrm{x})+\tan ^{-1}(3 \mathrm{x})=\frac{\pi}{4} \text { . } $$
\(\sin ^{-1} x>\cos ^{-1} x\) holds for (a) All values of \(x\) (b) \(\mathrm{x} \in\left(0, \frac{1}{\sqrt{2}}\right)\) (c) \(\mathrm{x} \in\left(\frac{1}{\sqrt{2}}, 1\right)\) (d) \(x \in\left(\frac{-1}{\sqrt{2}}, 0\right)\)
\(\sin x \cos x \cos 2 x=k\) has a solution if \(k\) lies between (a) \(-1\) and 1 (b) \(-\frac{1}{4}\) and \(\frac{1}{4}\) (c) \(-\frac{1}{2}\) and \(\frac{1}{2}\) (d) \(-\frac{1}{3}\) and \(\frac{1}{3}\)
\(\sin ^{4} \frac{\pi}{16}+\sin ^{4} \frac{3 \pi}{16}+\sin ^{4} \frac{5 \pi}{16}+\sin ^{4} \frac{7 \pi}{16}\) equals (a) \(2.5\) (b) \(1.5\) (c) \(2 \sqrt{2}\) (d) \(2 \sqrt{3}\)
$$ \text { Prove that } \cos ^{3} \alpha+\cos ^{3}\left(\frac{2 \pi}{3}+\alpha\right)+\cos ^{3}\left(\frac{4 \pi}{3}+\alpha\right)=\frac{3}{4} \cos 3 \alpha $$
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