Chapter 6: Problem 1
Bestimmen Sie die Lösungen der Differentialgleichungen (a) \(\left(x^{2}-1\right) y^{\prime}+2 x y^{2}=0\) (b) \(x y^{\prime}+y \ln y=0\) (c) \(y^{\prime}=2 x \frac{\cos ^{2} y}{1+x^{2}}\) (d) \(x y^{\prime}=\sqrt{x} y^{2}\) (e) \(y^{\prime}=\frac{\sinh y}{x^{2}+1}\) (f) \(y^{\prime \prime} \tan x=y^{\prime}+1\) (g) \(y^{\prime} \sin x=y^{2}-y\).
Short Answer
Step by step solution
Solving part (a)
Solving part (b)
Solving part (c)
Solving part (d)
Solving part (e)
Solving part (f)
Solving part (g)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Separable Differential Equation
- y' = -\frac{2xy^2}{x^2 - 1}
- \( \frac{dy}{y^2} = -\frac{2x}{x^2 - 1} \, dx \)
Integration Techniques
- Suppose we have after separation: \( \int \frac{dy}{y^2} = -2 \int \frac{x \, dx}{x^2 - 1} \).
- **Substitution Method**: Transforming complex expressions into simple, solvable integrals. For instance, integrating \( \frac{1}{x^2 - 1} \) might involve substitution to simplify.
- **Partial Fraction Decomposition**: Useful when the expression under the integral sign is a rational function that can be expressed as a sum of simpler fractions.
- **Integration by Parts**: Applied when the integral is a product of functions, using the parts formula \( \int u \, dv = uv - \int v \, du \).
- One side might integrate to logarithmic expressions as \( \int \frac{dy}{y^2} \) relating to \( -\frac{1}{y} \).
Solution of Differential Equations
- \( -\frac{1}{y} = -\log|x^2 - 1| + C \)
- \( y = -\frac{1}{\log|x^2 - 1| + C} \)