Chapter 1: Problem 55
$$ \underline{V}(x, y, z)=\left[\begin{array}{l} y \\ 0 \\ 0 \end{array}\right] $$
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 1: Problem 55
$$ \underline{V}(x, y, z)=\left[\begin{array}{l} y \\ 0 \\ 0 \end{array}\right] $$
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
Beweise, daß für den Darbouxschen Drehvektor \(\underline{D}(s)\) (s. (1.190)) folgende Formeln gelten: $$ \left.\begin{array}{rlr} \underline{T}^{\prime} & =\underline{D} \times \underline{T}= & \kappa \underline{N} \\ \underline{N}^{\prime} & =\underline{D} \times \underline{N}=-\kappa \underline{T} & +\tau \underline{B} \\ \underline{B}^{\prime} & =\underline{D} \times \underline{B}=\quad-\tau \underline{N} \end{array}\right\\} $$
Berechne das Potential von \(\underline{V}(\underline{x})=\underline{x} /|\underline{x}|^{2}, \underline{x}=\left[\begin{array}{l}x \\\ y\end{array}\right] \in \mathbb{R}^{2} \backslash\\{0\\}\), falls es existiert.
Leite die Parameterdarstellung der Astroide her. Benutze dabei die Formeln \(\cos (3 \alpha)=4 \cos ^{3} \alpha-3 \cos \alpha\) und \(\sin 3 \alpha=3 \sin \alpha-4 \sin ^{3} \alpha\).
Berechne die natürliche Parameterdarstellung des Kreises \(K\) und der Strecke \(S\) : $$ \begin{aligned} &K: x=r \cos (\omega t), y=r \sin (\omega t), t \in\left[0, \frac{2 \pi}{\omega}\right],(r>0, \omega>0) \\ &S: x=3 t-1, y=-5 t+2, t \in[0,1] \end{aligned} $$
$$ x^{2}-8 x y+10 y^{2}-x+5 y+2=0 $$
What do you think about this solution?
We value your feedback to improve our textbook solutions.