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For questions sketch a graph of the function and state its: a) domain and range; b) coordinates of any \(x\) -intercept(s) and \(y\) -intercept; \(c\) ) and the equation of any asymptote(s). $$h(x)=\frac{1}{1-e^{x}}$$

Short Answer

Expert verified
Domain: all real numbers except 0; Range: all real numbers except -1. Vertical asymptote: \(x = 0\); Horizontal asymptote: \(y = -1\). No intercepts.

Step by step solution

01

Understanding the Function

The function given is \( h(x) = \frac{1}{1-e^{x}} \). It involves an exponential function \( e^x \) in the denominator, which could lead to a vertical asymptote where the denominator equals zero.
02

Finding Domain

The domain of the function is found by setting \( 1 - e^x eq 0 \). Solving \( 1 - e^x = 0 \) gives \( e^x = 1 \), which means \( x = 0 \). Thus, the domain is all real numbers except \( x = 0 \).
03

Finding Range

The range of the function depends on the behavior of the function as \( x \) approaches the values in its domain. As \( x \to -\infty \), \( h(x) \to -1 \). As \( x \to 0^- \), \( h(x) \to \infty \), and as \( x \to 0^+ \), \( h(x) \to -\infty \). So, the range is all real numbers except \( h(x) = -1 \).
04

Finding Intercepts

To find the \( y \)-intercept, set \( x = 0 \). The function is undefined at \( x = 0 \), so there is no \( y \)-intercept. To find the \( x \)-intercept, set \( h(x) = 0 \), which leads to no real solution since \( \frac{1}{1-e^x} = 0 \) is not possible.
05

Finding Asymptotes

The vertical asymptote occurs where the denominator is zero, which is at \( x = 0 \). There is a horizontal asymptote as \( x \to \infty \), \( h(x) \to -1 \). Thus, the equations of the asymptotes are \( x = 0 \) and \( y = -1 \).
06

Sketching the Graph

With the information from previous steps, sketch the graph:- Draw a vertical asymptote at \( x = 0 \).- Draw a horizontal asymptote at \( y = -1 \).- Show the curve approaching \( -1 \) as \( x \to \infty \) and moving to infinity and \(-\infty\) as \( x \to 0 \) from either side.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Domain and Range
When studying the domain of a function, we're identifying all the x-values for which the function is defined. For the given function, \( h(x) = \frac{1}{1-e^{x}} \), the denominator must not be zero as this would make the function undefined. Therefore, we set \( 1 - e^{x} eq 0 \). Solving \( 1 - e^x = 0 \) gives us \( e^x = 1 \) or \( x = 0 \). This means the function is defined for all real numbers except \( x = 0 \). Thus, the domain is:
  • All real numbers \( \mathbb{R} \) except \( x = 0 \).
The range of a function tells us all possible outputs or y-values. By looking at the behavior of \( h(x) \), as \( x \to -\infty \), \( h(x) \to -1 \). As \( x \to 0^{-} \), it goes towards \( \infty \), and as \( x \to 0^{+} \), it heads to \( -\infty \). Therefore, the range is:
  • All real numbers except \( h(x) = -1 \).
Intercepts
Intercepts are points where the graph intersects the x-axis and y-axis. To find these, we can set the function equal to zero for x-intercepts and set \( x = 0 \) for y-intercepts. Let's talk about each:
  • X-intercepts: These occur where \( h(x) = 0 \). For \( \frac{1}{1-e^{x}} = 0 \), it would imply an undefined situation as a fraction equals zero when its numerator is zero, and here the numerator doesn't contain x. Hence, there are no x-intercepts for this function.
  • Y-intercepts: Setting \( x = 0 \) discovers \( h(0) \), however \( h(x) \) is undefined at \( x = 0 \). Thus, there are no y-intercepts in this case.
Graph Sketching
Graph sketching relies heavily on understanding asymptotic behavior, domain, range, and intercepts. Here’s how we can construct a basic sketch for \( h(x) = \frac{1}{1-e^{x}} \):
  • Vertical Asymptote: At \( x = 0 \), the function has a vertical asymptote, since the denominator becomes zero. This means the graph will approach this line but never touch it.
  • Horizontal Asymptote: As \( x \to \infty \), the value of \( e^{x} \) grows quickly, making the fraction approach a y-value of \( -1 \). Thus, \( y = -1 \) is a horizontal asymptote.
    • With these asymptotes, the graph should:
      • Approach \( -1 \) as \( x \to \infty \).
      • Move toward \( +\infty \) as \( x \to 0^{-} \) and toward \( -\infty \) as \( x \to 0^{+} \).
      Start by plotting the asymptotes and sketch the curve to accurately reflect how it behaves near these lines.

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