Chapter 3: Problem 42
If \(\alpha\) and \(\beta\) are the roots of the equation \(3 x^{2}+5 x+4=0,\) find the values of the following expressions a) \(\alpha^{2}+\beta^{2}\) b) \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\) c) \(\alpha^{3}+\beta^{3} \quad\) [Hint factorise \(\alpha^{3}+\beta^{3}\) into a product of a binomial and a trinomial
Short Answer
Step by step solution
Use Vieta's Formulas
Find \(\alpha^2 + \beta^2\)
Calculate \(\frac{\alpha}{\beta} + \frac{\beta}{\alpha}\)
Use a Hint to Simplify \(\alpha^3 + \beta^3\)
Final Calculation of \(\alpha^3 + \beta^3\)
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vieta's Formulas
- The sum of the roots \((\alpha + \beta)\) equals \(-\frac{b}{a}\).
- The product of the roots \((\alpha \beta)\) equals \(\frac{c}{a}\).
- \(\alpha + \beta = -\frac{5}{3}\)
- \(\alpha \beta = \frac{4}{3}\)
Roots of Quadratic Equation
- The quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) is typically used to find roots explicitly.
- However, properties and relationships between roots, such as those expressed through Vieta’s formulas, offer an alternative approach.
Polynomial Identities
- \(\alpha^2 + \beta^2 = (\alpha + \beta)^2 - 2\alpha\beta\)
- \(\alpha^3 + \beta^3 = (\alpha + \beta)(\alpha^2 - \alpha \beta + \beta^2)\)