Chapter 3: Problem 3
In questions, two polynomials \(P\) and \(D\) are given. Use either synthetic division or long division to divide \(P(x)\) by \(D(x)\), and express \(P(x)\) in the form \(P(x)=D(x) \cdot Q(x)+R(x)\). $$P(x)=x^{3}-5 x^{2}+3 x-7, D(x)=x-4$$
Short Answer
Expert verified
The division of \( P(x) \) by \( D(x) \) gives \( P(x) = (x - 4)(x^2 - x - 1) - 11 \).
Step by step solution
01
Setup for Synthetic Division
Since the divisor is of the form \( x - c \), we can use synthetic division. Here, \( c = 4 \). We'll write down the coefficients of \( P(x) = x^3 - 5x^2 + 3x - 7 \) in a row: \( 1, -5, 3, -7 \).
02
Perform Synthetic Division
1. Bring down the leading coefficient, \( 1 \), directly underneath the division line.\2. Multiply \( 4 \) by \( 1 \) and place the result \( 4 \) underneath the next coefficient \( -5 \).\3. Add \( -5 + 4 \) to get \( -1 \) and write the result.\4. Continue multiplying and adding: Multiply \( 4 \) by \( -1 \), place \(-4\) under \(3\); sum to get \(-1\). Multiply \( 4 \) by \(-1\), place \(-4\) under \(-7\); sum to get \(-11\).\ The final row of numbers is \( 1, -1, -1, -11 \).
03
Interpret the Results
The numbers from the synthetic division represent the coefficients of the quotient polynomial \( Q(x) \) and the remainder \( R(x) \). The formula is:\[ Q(x) = x^2 - x - 1 \] (since the divisor was \( x-4 \), degree reduction by 1), and the remainder is \( R(x) = -11 \).
04
Express in Polynomial Form
Using the division equation, express \( P(x) \):\[ P(x) = (x - 4)(x^2 - x - 1) - 11 \]This represents \( P(x) \) in the form \( D(x) \cdot Q(x) + R(x) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
synthetic division
Synthetic division is a streamlined form of polynomial division, specifically used when the divisor is a linear polynomial of the form \(x - c\). This method greatly simplifies the division process, making it quicker and less cumbersome compared to traditional long division. Here’s how you can effectively perform synthetic division:
- First, identify \(c\), the constant from your linear divisor \(x - c\).
- Write down the coefficients of the dividend polynomial \(P(x)\) in descending order of powers. If any terms are missing, fill them with zeros.
- Bring down the leading coefficient. Multiply it by \(c\) and add the result to the next coefficient. Repeat this process across all coefficients.
- The numbers obtained in the bottom row represent the coefficients of the quotient and, finally, the remainder.
long division
Polynomial long division is a useful method for dividing a polynomial by another polynomial of any degree. Although often seen as more complex than synthetic division, it's highly versatile. Here’s a breakdown of how to use long division for polynomials:
- Set up the division as you would with numbers, placing the dividend (the polynomial being divided) inside the division symbol and the divisor outside.
- Divide the leading term of the dividend by the leading term of the divisor. This will be the first term of your quotient.
- Multiply the entire divisor by this new term and subtract the result from the dividend.
- Bring down the next term, and repeat the process until all terms have been accounted for.
remainder theorem
The Remainder Theorem is a key concept in algebra, offering a quick way to find the remainder of a polynomial division without performing the entire division process. It states that for a polynomial \(P(x)\) divided by \(x - c\), the remainder is simply \(P(c)\).For example, if we divided \(P(x) = x^3 - 5x^2 + 3x - 7\) by \(x - 4\), according to the Remainder Theorem, the remainder can be found by evaluating \(P(4)\). Substituting 4 into the original polynomial gives:\[P(4) = 4^3 - 5(4)^2 + 3(4) - 7 = 64 - 80 + 12 - 7 = -11\]Thus, the remainder is \(-11\), confirming what was found through synthetic division.The Remainder Theorem is not only useful for verifying the result of a division but also for evaluating whether a number is a root of the polynomial (as the remainder will be zero if it is a root). It allows us to check division outcomes quickly, effectively bridging the gap between polynomial division processes and basic polynomial evaluation.