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A certain internet service website receives on average 0.2 hits per second. It is known that the number of hits on this site follows a Poisson distribution. a) Find the probability that no hits are registered during the next second. b) Find the probability that no hits are registered for the next 3 seconds.

Short Answer

Expert verified
a) e^{-0.2}; b) e^{-0.6}.

Step by step solution

01

Understanding Poisson Distribution

The Poisson distribution is used for counting the number of events occurring within a fixed interval of time or space, where each event happens with a constant mean rate and independently of the time since the last event. The formula for the Poisson probability is \( P(X=k) = \frac{{ ext{e}^{-\lambda} \lambda^k}}{k!} \), where \( \lambda \) is the average rate (mean) of occurrence, and \( k \) is the number of occurrences we want to find probability for.
02

Set Parameters for Part-a

For part-a, we need to find the probability of receiving no hits (0 hits) in the next second. The average rate \( \lambda \) is 0.2 hits per second.
03

Calculate Probability for Part-a

Using the Poisson probability formula for \( k = 0 \) and \( \lambda = 0.2 \), calculate \( P(X=0) = \frac{{ ext{e}^{-0.2} \cdot 0.2^0}}{0!} \). This simplifies to \( P(X=0) = ext{e}^{-0.2} \).
04

Set Parameters for Part-b

For part-b, we need to find the probability of receiving no hits in the next 3 seconds. Thus, the new average rate \( \lambda \) is \( 0.2 \times 3 = 0.6 \).
05

Calculate Probability for Part-b

Using the Poisson formula with \( k = 0 \) and \( \lambda = 0.6 \), calculate \( P(X=0) = \frac{{ ext{e}^{-0.6} \cdot 0.6^0}}{0!} \). This simplifies to \( P(X=0) = ext{e}^{-0.6} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory is a fascinating area of mathematics that allows us to understand and analyze random phenomena. It provides a theoretical framework to calculate the likelihood of events in uncertain situations. This is particularly useful when dealing with complex systems where precise predictions are difficult.

In probability theory, we work with concepts like random variables, which can take on different outcomes based on certain probabilities. An example of this is determining the probability that a specific number of events occur within a given timeframe. We use various mathematical models to evaluate these probabilities.

The Poisson distribution is one such model, particularly useful in scenarios where events occur independently and at a constant mean rate, such as website hits or lightbulb failures. Understanding probability theory is key to solving problems involving random events efficiently and accurately.
Counting Events
Counting events is an essential part of analyzing situations where we want to determine how often something happens within a specified time or space. Consider events like cars passing through a toll booth or calls received at a call center.

The Poisson distribution is prominently used in these scenarios because it is designed for counting discrete events. This distribution shows the probability of a certain number of events occurring in a fixed time period, given a known average rate of occurrence.
  • The events must be independent; the occurrence of one doesn't affect another.
  • The average number of events (mean rate) is constant.
  • The number of events counted in a time interval must be an integer.
When we use the Poisson distribution, we calculate the probability of a specific number of events using the formula: \[ P(X=k) = \frac{{\text{e}^{-\lambda} \lambda^k}}{k!} \]where \( \lambda \) is the mean rate, and \( k \) is the number of events we're counting.
Mean Rate
The mean rate is a crucial parameter in the Poisson distribution, representing the average number of events expected to occur in a unit of time or space. It helps us to understand the underlying dynamics of a system where events happen randomly.

In the context of the exercise, the mean rate \( \lambda \) was given as 0.2 hits per second. This means, on average, every second the website is expected to receive 0.2 hits, which simplifies to one hit every five seconds. However, because the distribution is random, sometimes there might be more hits, sometimes fewer.

When calculating probabilities over a different time frame (such as 3 seconds in part-b of the problem), the mean rate adjusts accordingly. For instance, over three seconds, \( \lambda \) becomes 0.6, reflecting the cumulative expected hits over those three seconds.

Thus, the mean rate not only helps in setting up the problem mathematically but also provides insight into the typical behavior of the system being studied, allowing us to make informed predictions about event occurrences.

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Most popular questions from this chapter

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