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A satellite relies on solar cells for its power and will operate provided that at least one of the cells is working. Cells fail independently of each other, and the probability that an individual cell fails within one year is 0.8. a) For a satellite with ten solar cells, find the probability that all ten cells fail within one year. b) For a satellite with ten solar cells, find the probability that the satellite is still operating at the end of one year. c) For a satellite with \(n\) solar cells, write down the probability that the satellite is still operating at the end of one year. Hence, find the smallest number of solar cells required so that the probability of the satellite still operating at the end of one year is at least 0.95

Short Answer

Expert verified
a) 0.1074 b) 0.8926 c) 19 cells.

Step by step solution

01

Probability of All Cells Failing

The probability that an individual solar cell fails within one year is given as 0.8. For ten independent cells, the probability that all cells fail is the probability of cell failure raised to the power of the number of cells: \[ P(\text{all fail}) = 0.8^{10} \] Calculate:\[ 0.8^{10} \approx 0.1074 \] Thus, the probability that all ten cells fail within one year is approximately 0.1074.
02

Probability of Satellite Operating

To find the probability that at least one cell is operating, use the complement of the probability that all cells fail:\[ P(\text{at least one working}) = 1 - P(\text{all fail}) = 1 - 0.8^{10} \] Plugging in the value from Step 1:\[ 1 - 0.8^{10} \approx 1 - 0.1074 = 0.8926 \] Thus, the probability that the satellite is still operating at the end of one year is approximately 0.8926.
03

General Probability for n Cells

For a satellite with \( n \) solar cells, the probability that it is still operating is:\[ P(\text{operating}) = 1 - (0.8)^n \] This represents the probability that not all cells have failed by the end of one year.
04

Minimum Solar Cells for 95% Probability

We want the probability of the satellite operating to be at least 0.95:\[ 1 - (0.8)^n \geq 0.95 \] Rearrange to solve for \( n \):\[ (0.8)^n \leq 0.05 \] Taking the logarithm of both sides:\[ n \cdot \ln(0.8) \leq \ln(0.05) \] \[ n \geq \frac{\ln(0.05)}{\ln(0.8)} \]Calculate:\[ n \geq \frac{\ln(0.05)}{\ln(0.8)} \approx 18.4 \] Rounding up, the smallest number of solar cells required is 19.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Satellite Power Systems
Satellites rely heavily on efficient power systems to function properly. Their primary source of power often includes solar cells, which convert solar energy into electricity. These cells are vital for the continuous operation of satellites as they traverse areas in space where sunlight is accessible.

In the context of satellite power systems, if a satellite has a series of solar cells, it is important that at least one cell remains functioning for the satellite to continue operating. This is because the satellite would otherwise lack the energy to manage critical operations like communication, data processing, or adjusting its trajectory.
  • Each solar cell independently contributes to the total energy needs.
  • If one solar cell fails, the others can still supply energy.
  • This concept of operational redundancy is crucial in satellite power design.
Understanding how to calculate the probability of these systems remaining functional over time is rooted in probability theory, where we analyze how likely it is for a series of components (like solar cells) to continue functioning.
Independent Events
In probability theory, events are considered independent if the occurrence of one does not affect the probability of the other occurring. For satellite solar cells, this independence is key, as the failure of one cell does not impact the failure probability of another cell.

When calculating probabilities for independent events, the multiplication rule is applied. For example, the probability that all cells fail is simply the product of individual failure probabilities raised to the number of cells:
  • Let the probability a single cell fails be 0.8.
  • For ten cells, all failing independently, the probability is \( 0.8^{10} \).
  • This gives a result of approximately 0.1074, meaning all cells failing simultaneously in a year is relatively low.
These principles of independent events allow for a systematic approach to assessing and managing risks, especially in engineering domains like aerospace.
Complementary Probability
Complementary probability is a useful concept in probability theory, referring to the probability of an event not occurring. If you know the probability of an event happening, you can easily find the complementary probability by subtracting it from one.

In the context of satellite solar cells:
  • The probability of all cells failing (which is an undesirable event) is calculated as \( 0.8^{10} \).
  • The probability of the satellite operating (at least one cell working) is the complement: \( 1 - 0.8^{10} \).
  • This gives approximately 0.8926, meaning the satellite is likely to operate for a year.
By understanding complementary probability, one can assess the likelihood of success versus failure, providing insights into the reliability and effectiveness of complex systems like satellites.
Logarithmic Calculations
Logarithmic calculations are fundamental when solving for unknown exponents, such as determining the number of solar cells needed to meet specific probabilities. In this case, logarithms help solve equations where the probabilities are set.

For determining the smallest number of solar cells required to ensure a 95% success probability:
  • We use \( 1 - (0.8)^n \geq 0.95 \).
  • Rearranging the inequality gives \( (0.8)^n \leq 0.05 \).
  • Taking logarithms of both sides yields \( n \cdot \ln(0.8) \leq \ln(0.05) \).
  • Solve for \( n \) to find \( n \geq \frac{\ln(0.05)}{\ln(0.8)} \approx 18.4 \).
  • Since \( n \) must be a whole number, round up to 19.
This step reveals the power of logarithmic calculations in making precise predictions and designing robust systems that withstand potential failures.

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