Chapter 14: Problem 15
Find an equation for the plane satisfying the given conditions. Give two forms for each equation out of the three forms: Cartesian, vector or parametric. Contains the two parallel lines $$\mathbf{r}=(1,-1,5)+t(3 \mathbf{i}+2 \mathbf{j}+4 \mathbf{k}) \text { and } \mathbf{r}=(-3,4,0)+t(3 \mathbf{i}+2 \mathbf{j}+4 \mathbf{k})$$
Short Answer
Step by step solution
Determine a normal vector to the plane
Find a point on the plane
Form a vector between the points
Check the vector independence
Cartesian form of the plane equation
Vector form of the plane equation
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Vector Algebra
To interpret a vector, you think of it as an arrow that points from one location to another. The direction vector, such as \( \mathbf{d} = (3, 2, 4) \), provides the direction in which our line extends.
When two lines share the same direction vector, as in our exercise, it indicates that they are parallel. Knowing two vectors on a plane, such as our direction vector and the vector \( \mathbf{v} = (-4, 5, -5) \) between two points, helps us to define that plane, provided these vectors are linearly independent.
- Linear independence means the vectors are not scalar multiples of each other, allowing them to span a plane.
- If two vectors are dependent (one is a multiple of the other), they do not define a plane as they lie along the same line.
Parametric Form of a Plane
In our solution, the parametric form is given by \( \mathbf{r}(s, t) = (1, -1, 5) + s(3, 2, 4) + t(-4, 5, -5) \). This equation describes all positions \( \mathbf{r} \) on the plane as a combination of a fixed point and scaled vectors.
The vectors \( (3, 2, 4) \) and \( (-4, 5, -5) \) are direction vectors achieving any point on the plane when adjusted by changing parameters \( s \) and \( t \).
- Start from the fixed point \( (1, -1, 5) \), which lies on the plane.
- Adjust \( s \) and \( t \) to navigate across the plane in the direction of each vector.
- Each combination of \( s \) and \( t \) leads to a unique point on the plane, showcasing the plane's entire surface.
Cartesian Form of a Plane
In the exercise, the Cartesian equation is found as \( 3x + 2y + 4z = 27 \). This form relates the variables \( x, y, \) and \( z \) with the plane's position by representing how far each direction reaches.
To define this form:
- The coefficients \( 3, 2, \) and \( 4 \) emerge from the normal vector \( (3, 2, 4) \), establishing the plane's orientation.
- Point substitution, such as substituting \((1, -1, 5)\), helps derive the constant on the right, \( 27 \), ensuring the equation represents the desired plane through the chosen point.