Chapter 10: Problem 49
Given that \(z=(k+i)^{4}\) where \(k\) is a real number, find all values of \(k\) such that a) \(z\) is a real number b) \(z\) is purely imaginary.
Short Answer
Expert verified
For real z: \(k = 0, 1, -1\). For purely imaginary z: \(k = \pm\sqrt{3+2\sqrt{2}}, \pm\sqrt{3-2\sqrt{2}}\).
Step by step solution
01
Expand the expression for z
The expression given is \(z = (k+i)^4\). Use the binomial theorem to expand this. The binomial theorem states \((a+b)^n = \sum_{r=0}^{n} \binom{n}{r} a^{n-r} b^r\). Applying it here:\[(k+i)^4 = \binom{4}{0}k^4 + \binom{4}{1}k^3(i) + \binom{4}{2}k^2(i)^2 + \binom{4}{3}k(i)^3 + \binom{4}{4}(i)^4\] Simplify using powers of \(i\):\[(i)^2 = -1,\ (i)^3 = -i,\ (i)^4 = 1\]This yields:\[z = k^4 + 4k^3i + 6k^2(-1) + 4k(-i) + 1 = k^4 - 6k^2 + 1 + (4k^3 - 4k)i\]
02
Set imaginary part to zero for real z
For \(z\) to be a real number, its imaginary part must be zero. From the expansion, the imaginary part is \(4k^3 - 4k\). Set this equal to zero:\[4k^3 - 4k = 0\]Factor out a \(4k\):\[4k(k^2 - 1) = 0\]This gives solutions:\[k = 0,\ k^2 - 1 = 0\]Solving \(k^2 - 1 = 0\) gives \(k = \pm 1\). Hence, \(k = 0, 1, -1\).
03
Check k values for when z is real
Substitute \(k = 0, 1, -1\) back into the expression for \(z\):- For \(k = 0\), \(z = 0^4 - 6 \times 0^2 + 1 = 1\), real.- For \(k = 1\), \(z = 1^4 - 6 \times 1^2 + 1 = -4\), real.- For \(k = -1\), \(z = (-1)^4 - 6((-1)^2) + 1 = -4\), real.All values confirm \(z\) is real.
04
Set real part to zero for purely imaginary z
For \(z\) to be purely imaginary, its real part must be zero. From the expansion, the real part is \(k^4 - 6k^2 + 1\). Set this equal to zero:\[k^4 - 6k^2 + 1 = 0\].This is a quadratic in terms of \(k^2\) (let \(u = k^2\)): \[u^2 - 6u + 1 = 0\].Solve this quadratic using the quadratic formula:\[u = \frac{6 \pm \sqrt{36 - 4}}{2}\], \[u = 3 \pm 2\sqrt{2}\].Thus, \(k^2 = 3 \pm 2\sqrt{2}\).
05
Find k values for purely imaginary z
Solve for \(k\) from \(k^2 = 3 \pm 2\sqrt{2}\):- For \(k^2 = 3 + 2\sqrt{2}\), \(k = \pm\sqrt{3 + 2\sqrt{2}}\).- For \(k^2 = 3 - 2\sqrt{2}\), \(k = \pm\sqrt{3 - 2\sqrt{2}}\).These values of \(k\) ensure that the real part of \(z\) is zero, making \(z\) purely imaginary.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Theorem
The Binomial Theorem is a powerful formula used for expanding expressions that are raised to a power. In simpler terms, it helps us expand expressions of the form \((a+b)^n\). This theorem tells us that we can express the expanded form as a sum of terms using combinations. The general formula is given by: \[(a+b)^n = \sum_{r=0}^{n} \binom{n}{r} a^{n-r} b^r\]This formula might look complex at first, but let's break it down:
- \(n\) is the power to which the expression is raised.
- \(\binom{n}{r}\) is a combination, representing the number of ways to choose \(r\) elements from \(n\) elements, and it can be calculated as \( \frac{n!}{r!(n-r)!} \).
- \(a^{n-r}\) and \(b^r\) represent the terms that you are multiplying.
Imaginary Numbers
Imaginary numbers are a fascinating concept in mathematics, extending our number system. The basic idea starts with the imaginary unit \(i\), defined as the square root of \(-1\). This means:
\[i^2 = -1\]
Imaginary numbers are numbers that can be written as a real number multiplied by \(i\). For example, \(2i\) or \(-3i\) are imaginary numbers. These numbers do not exist on the traditional number line but rather on a perpendicular axis called the imaginary axis, used in what's known as the complex plane.
In the complex plane:
\[i^2 = -1\]
Imaginary numbers are numbers that can be written as a real number multiplied by \(i\). For example, \(2i\) or \(-3i\) are imaginary numbers. These numbers do not exist on the traditional number line but rather on a perpendicular axis called the imaginary axis, used in what's known as the complex plane.
In the complex plane:
- The horizontal axis represents real numbers.
- The vertical axis represents imaginary numbers.
Real Numbers
Real numbers are the numbers we interact with daily, encompassing a wide variety from whole numbers both positive and negative, to fractions and irrational numbers. Real numbers can be found on the typical number line.
Real numbers include:
Real numbers include:
- Natural numbers like 1, 2, 3, etc.
- Integers, which extend positive and negative whole numbers, including zero.
- Rational numbers, which are any numbers that can be expressed as a fraction \(\frac{p}{q}\) where \(p\) and \(q\) are integers and \(q eq 0\).
- Irrational numbers, which cannot be expressed as simple fractions. They have decimal expansions that never repeat or terminate, such as \(\pi\) or \(\sqrt{2}\).