Chapter 10: Problem 34
Find the modulus and argument (amplitude) of each of the complex numbers $$z_{1}=2 \sqrt{3}-2 i, z_{2}=2+2 i \text { and } z_{3}=(2 \sqrt{3}-2 i)(2+2 i)$$
Short Answer
Expert verified
The moduli of \( z_1, z_2, z_3 \) are 4, \( 2\sqrt{2} \), and \( 4\sqrt{2} \). The arguments are \( -\frac{\pi}{6} \), \( \frac{\pi}{4} \), and \( \frac{\pi}{2} \) respectively.
Step by step solution
01
Identify the Complex Number Components
The complex numbers given are \( z_1 = 2\sqrt{3} - 2i \) and \( z_2 = 2 + 2i \). For each complex number \( z = a + bi \), where \( a \) is the real part and \( b \) is the imaginary part.
02
Calculate Modulus of z1
The modulus of a complex number \( z = a + bi \) is given by \( |z| = \sqrt{a^2 + b^2} \). For \( z_1 = 2\sqrt{3} - 2i \), the modulus is \( |z_1| = \sqrt{ (2\sqrt{3})^2 + (-2)^2 } = \sqrt{12 + 4} = \sqrt{16} = 4 \).
03
Calculate Argument of z1
The argument \( \theta \) of a complex number \( z = a + bi \) is \( \theta = \tan^{-1}(\frac{b}{a}) \). For \( z_1 = 2\sqrt{3} - 2i \), \( \theta = \tan^{-1}\left(\frac{-2}{2\sqrt{3}}\right) = \tan^{-1}\left(-\frac{1}{\sqrt{3}}\right) = -\frac{\pi}{6} \).
04
Calculate Modulus of z2
Using the same formula for modulus, for \( z_2 = 2 + 2i \), the modulus is \( |z_2| = \sqrt{2^2 + 2^2} = \sqrt{8} = 2\sqrt{2} \).
05
Calculate Argument of z2
For \( z_2 = 2 + 2i \), the argument \( \theta = \tan^{-1}\left(\frac{2}{2}\right) = \tan^{-1}(1) = \frac{\pi}{4} \).
06
Calculate Product z3
For \( z_3 = (2\sqrt{3} - 2i)(2 + 2i) \), distribute the terms: \[(2\sqrt{3} \cdot 2 + 2\sqrt{3} \cdot 2i - 2 \cdot 2 - 2 \cdot 2i) = (4\sqrt{3} + 4\sqrt{3}i - 4 - 4i) = 4\sqrt{3} - 4 + (4\sqrt{3} - 4)i)\]Calculating further: The real part is \( 4\sqrt{3} - 4 \)The imaginary part is \( 4\sqrt{3} - 4 \).
07
Calculate Modulus of z3
Using the modulus formula on \( z_3 \), we have:\[|z_3| = \sqrt{(4\sqrt{3} - 4)^2 + (4\sqrt{3} - 4)^2}\]Simplifying, this expresses to:\[= \sqrt{2(4\sqrt{3} - 4)^2} = \sqrt{2(48 + 32 - 32\sqrt{3})}\]\[= \sqrt{160 - 64\sqrt{3}} = 4\sqrt{10 - 4\sqrt{3}}\]
08
Calculate Argument of z3
For argument of \( z_3 \), since both real and imaginary parts are equal, the argument is 45° or equivalently \( \frac{\pi}{4} \) radians, plus \( 180 \) degrees if necessary for correct quadrants.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Modulus of a Complex Number
The modulus of a complex number is a measure of its "size" or "length" in the complex plane. A complex number is generally written in the form \( z = a + bi \), where \( a \) is the real part and \( b \) is the imaginary part. To find the modulus, we use the formula:
- \( |z| = \sqrt{a^2 + b^2} \)
- \( |z_1| = \sqrt{(2\sqrt{3})^2 + (-2)^2} = \sqrt{12 + 4} = \sqrt{16} = 4 \)
Argument of a Complex Number
The argument of a complex number is the angle formed with the positive direction of the x-axis (real axis), and is crucial for fully understanding the placement of the complex number in the complex plane. For a complex number written as \( z = a + bi \), the argument \( \theta \) is given by:
- \( \theta = \tan^{-1}\left(\frac{b}{a}\right) \)
- \( \theta = \tan^{-1}\left(\frac{2}{2}\right) = \tan^{-1}(1) = \frac{\pi}{4} \)
Step-by-Step Mathematical Solution
Solving for the modulus and argument of a complex number can be done systematically. Each step builds on the previous one:
- Identify Components: Clearly label the real part \( a \) and imaginary part \( b \) from the form \( z = a + bi \).
- Calculate Modulus: Use the formula \( |z| = \sqrt{a^2 + b^2} \) to find the modulus. Check each calculation for accuracy.
- Determine Argument: Apply the formula \( \theta = \tan^{-1}\left(\frac{b}{a}\right) \) to find the angle. Adjust for the correct quadrant.
- Handle Complex Operations: When dealing with products like \( z_3 = (2\sqrt{3} - 2i)(2 + 2i) \), distribute and simplify before finding modulus and argument.