Chapter 1: Problem 30
Completely factorize the expression. $$x^{4}-1$$
Short Answer
Expert verified
\((x^2 + 1)(x + 1)(x - 1)\)
Step by step solution
01
Recognize the Difference of Squares
The expression given, \(x^4 - 1\), can be recognized as a difference of squares. This is because it can be written as \((x^2)^2 - (1)^2\), which is in the form \(a^2 - b^2\).
02
Apply the Difference of Squares Formula
The difference of squares formula states that \(a^2 - b^2 = (a+b)(a-b)\). Applying this to \(x^4 - 1 = (x^2)^2 - 1^2\), we get \((x^2 + 1)(x^2 - 1)\).
03
Recognize Another Difference of Squares
Notice that \(x^2 - 1\) is also a difference of squares. Using \(a^2 - b^2 = (a+b)(a-b)\) again, where \(a = x\) and \(b = 1\), we can factor \(x^2 - 1\) as \((x + 1)(x - 1)\).
04
Write the Completely Factorized Expression
Our factored form of \(x^4 - 1\) now becomes \((x^2 + 1)(x + 1)(x - 1)\). There are no further factors since \(x^2 + 1\) cannot be further factorized with real numbers.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Difference of Squares
The difference of squares is a handy concept in algebra when dealing with expressions that can be rewritten in a specific way. To understand it, consider the expression \( a^2 - b^2 \). This expression can always be factored into the product \( (a + b)(a - b) \).This strategy works because when you expand \( (a + b)(a - b) \), the terms \( ab \) and \( -ab \) cancel each other out, leaving you with just \( a^2 - b^2 \).In our example, \( x^4 - 1 \), by identifying it as \( (x^2)^2 - 1^2 \), we recognize it's a difference of squares:
- \( a = x^2 \)
- \( b = 1 \)
Factoring Quadratic Expressions
Factoring quadratic expressions involves rewriting a quadratic expression as a product of its linear factors. A quadratic expression is usually written in the form: \( ax^2 + bx + c \).For the expression \( x^2 - 1 \), which is part of our factorization of \( x^4 - 1 \), it's a special case often called the "difference of squares," a specific type of quadratic. We've already broken it down as \( (x + 1)(x - 1) \)using the difference of squares formula. This means we're finding the values of \( x \) where the expression equals zero.To factor quadratic expressions in general, you can:
- Find two numbers that multiply to \( ac \) and add to \( b \).
- Rewrite \( bx \) using those numbers to split the middle term.
- Factor by grouping.
Completing the Square
Completing the square is another method for transforming quadratic expressions into a different form which is highly useful for solving equations or graphing quadratics. This technique involves rearranging the quadratic expression into a perfect square trinomial.For our expression \( x^2 + 1 \), completing the square isn't directly applicable over real numbers because it doesn't become a perfect square with real coefficients. However, understanding the concept is important. Here's the general idea:
- Rewrite the quadratic in the form \( (x + d)^2 + e \), where \( e \) is an additional constant.
- The goal is to express \( x^2 + 2dx + d^2 \) within your expression as \( (x + d)^2 \).
- Adjust the expression to ensure it remains equivalent by adding and subtracting the same value.