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Find the equation of the line that passes through the two given points. Write the line in slope-intercept form \((y=m x+c)\), if possible. $$(-12,-9) \text { and }(4,11)$$

Short Answer

Expert verified
The equation of the line is \(y = \frac{5}{4}x + 6.\)

Step by step solution

01

Calculate the Slope

To find the equation of a line in slope-intercept form, we first need to calculate the slope \(m\) using the formula \(m = \frac{y_2 - y_1}{x_2 - x_1}\). Let \((x_1, y_1) = (-12, -9)\) and \((x_2, y_2) = (4, 11)\). Substituting these values into the formula gives:\[m = \frac{11 - (-9)}{4 - (-12)} = \frac{11 + 9}{4 + 12} = \frac{20}{16} = \frac{5}{4}.\]So, the slope \(m\) is \(\frac{5}{4}.\)
02

Use the Slope-Point Form

Using the slope-point form \( y - y_1 = m(x - x_1) \) with the slope \( m = \frac{5}{4} \) and one of the given points. Let's use \((x_1, y_1) = (4, 11)\):\[ y - 11 = \frac{5}{4}(x - 4). \]
03

Simplify to Slope-Intercept Form

Simplify the equation from Step 2 into the slope-intercept form \(y = mx + c\):\[y - 11 = \frac{5}{4}x - \frac{5}{4} \times 4,\]\[y - 11 = \frac{5}{4}x - 5.\]Add 11 to both sides to isolate \(y\):\[y = \frac{5}{4}x + 6.\]Thus, the equation of the line in slope-intercept form is \(y = \frac{5}{4}x + 6.\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope-Intercept Form
The slope-intercept form of a linear equation is one of the most straightforward ways to express the equation of a line. It is written as:
  • \( y = mx + c \)
In this format, \( m \) represents the slope of the line, while \( c \) represents the y-intercept. The y-intercept is the point where the line crosses the y-axis, and it tells us the value of \( y \) when \( x = 0 \). This form is particularly useful because it provides a quick visual understanding of a line's characteristic from its equation directly.
For example, with the equation \(y = \frac{5}{4}x + 6\), we instantly know that:
  • The slope is \( \frac{5}{4} \)
  • The y-intercept is 6, meaning the line crosses the y-axis at (0, 6).
Point-Slope Form
The point-slope form is a powerful way to write the equation of a line when it is easy for you to identify a slope and a specific point. It is expressed as:
  • \( y - y_1 = m(x - x_1) \)
Here, \((x_1, y_1)\) is a point on the line, and \(m\) is the slope. The point-slope form is particularly helpful for constructing the equation of a line when you are given the slope and a point, or two points that you can use to find the slope.
For instance, if you have calculated the slope \(m = \frac{5}{4}\) and have a known point like \((4, 11)\), you can plug these into the point-slope formula. This is why we derive:
  • \( y - 11 = \frac{5}{4}(x - 4) \)
This form helps us transition smoothly into writing the equation in the slope-intercept form.
Calculating Slope
The slope of a line is crucial as it indicates the line's steepness and its direction (upwards or downwards). To calculate the slope when you have two points, use the formula:
  • \( m = \frac{y_2 - y_1}{x_2 - x_1} \)
Simply, \( y_1 \) and \( y_2 \) are the y-coordinates of two different points, and \( x_1 \) and \( x_2 \) are their respective x-coordinates. This formula calculates the "rise over run," or how much the line goes up or down for each unit it goes across.
For example, with points \((-12, -9)\) and \((4, 11)\), we determine:
  • \( m = \frac{11-(-9)}{4-(-12)} = \frac{20}{16} = \frac{5}{4} \)
Such calculations help us not only write the line's equation but also understand the line's behavior relative to these markers.

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