Chapter 44: Problem 8
Find \(\int \frac{3+6 x+4 x^{2}-2 x^{3}}{x^{2}\left(x^{2}+3\right)} \mathrm{d} x\).
Short Answer
Expert verified
The integral is \(-2 \ln |x| - \frac{1}{x} + \frac{2}{\sqrt{3}} \arctan \left( \frac{x}{\sqrt{3}} \right) + C\).
Step by step solution
01
Decomposition into Partial Fractions
The integrand can be expressed as a sum of simpler fractions. For the given expression, we consider the form: \[ \frac{3 + 6x + 4x^2 - 2x^3}{x^2(x^2 + 3)} = \frac{A}{x} + \frac{B}{x^2} + \frac{Cx + D}{x^2 + 3} \]Identify and solve for the constants \(A\), \(B\), \(C\), and \(D\) by equating the coefficients after multiplying through by the common denominator \(x^2(x^2 + 3)\).
02
Solve for Coefficients
Set up the equation: \[ 3 + 6x + 4x^2 - 2x^3 = A(x)(x^2 + 3) + B(x^2 + 3) + (Cx + D)x^2 \]After expansion, collect like terms for powers of \(x\), and equate coefficients to find:- \(A = -2\)- \(B = 1\)- \(C = 0\)- \(D = 2\).
03
Express the Integral in Partial Fractions
Rewrite the integral with the coefficients obtained:\[ \int \left( \frac{-2}{x} + \frac{1}{x^2} + \frac{2}{x^2 + 3} \right) \mathrm{d}x \]The original integral has now been decomposed into a sum of simpler fractions suitable for integration.
04
Integrate Each Term Separately
Integrate each term using standard integral formulas:\[ \int \frac{-2}{x} \mathrm{d}x = -2 \ln |x| + C_1 \]\[ \int \frac{1}{x^2} \mathrm{d}x = -\frac{1}{x} + C_2 \]\[ \int \frac{2}{x^2 + 3} \mathrm{d}x = \frac{2}{\sqrt{3}} \arctan \left( \frac{x}{\sqrt{3}} \right) + C_3 \]
05
Combine Solutions to the Integral
Combine all parts to write the solution for the given integral:\[ -2 \ln |x| - \frac{1}{x} + \frac{2}{\sqrt{3}} \arctan \left( \frac{x}{\sqrt{3}} \right) + C \] where \(C = C_1 + C_2 + C_3\) is the constant of integration.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Integration Techniques
Integration techniques are essential tools for solving a wide variety of integrals. One such method is known as **integration by partial fractions**. This technique allows us to decompose complex rational functions into simpler fractions called partial fractions. By breaking down a complicated integral into simpler, more manageable pieces, we can integrate each part individually and then combine the results.
For instance, consider the expression \[\frac{3 + 6x + 4x^2 - 2x^3}{x^2(x^2 + 3)}\]In this exercise, we decompose the function into simpler fractions like:
For instance, consider the expression \[\frac{3 + 6x + 4x^2 - 2x^3}{x^2(x^2 + 3)}\]In this exercise, we decompose the function into simpler fractions like:
- \(\frac{A}{x}\) - where \(A\) is a constant
- \(\frac{B}{x^2}\) - another constant \(B\)
- \(\frac{Cx + D}{x^2 + 3}\) - a linear expression in the numerator
Definite Integrals
While dealing with integrals, it's important to distinguish between **definite and indefinite integrals**. This problem is solved as an indefinite integral, as observed by the presence of a constant of integration, \(C\). However, if given limits, this would become a definite integral which represents the area under the curve between those limits.
For definite integrals, we calculate a numeric value, depending on the limits of integration, usually notated as:\[\int_{a}^{b} f(x) \, \mathrm{d}x\]This result provides the net area under the curve from \(x = a\) to \(x = b\). It is an essential concept to understand the application of integrals in real-world scenarios, like finding displacement over time from a velocity function.
For definite integrals, we calculate a numeric value, depending on the limits of integration, usually notated as:\[\int_{a}^{b} f(x) \, \mathrm{d}x\]This result provides the net area under the curve from \(x = a\) to \(x = b\). It is an essential concept to understand the application of integrals in real-world scenarios, like finding displacement over time from a velocity function.
Mathematical Decomposition
Mathematical decomposition is foundational for simplifying complex expressions and solving equations. In integration, especially with partial fractions, decomposition involves expressing one fraction as a sum of simpler fractions.
In this exercise, we achieved decomposition by setting:
In this exercise, we achieved decomposition by setting:
- The original complex fraction \(\frac{3 + 6x + 4x^2 - 2x^3}{x^2(x^2 + 3)}\) as the sum of simpler fractions like \(\frac{A}{x}\) and \(\frac{B}{x^2}\).
- Then, we determined the coefficients \(A, B, C,\) and \(D\) by equating coefficients after clearing the common denominator.