Chapter 20: Problem 9
Determine the asymptotes parallel to the \(x\) - and \(y\)-axes for the function $$ x^{2} y^{2}=9\left(x^{2}+y^{2}\right) $$
Short Answer
Expert verified
Asymptotes are \( y = \pm 3 \) (horizontal) and \( x = \pm 3 \) (vertical).
Step by step solution
01
Rewrite the Equation
Starting with the given equation \( x^2 y^2 = 9(x^2 + y^2) \), we rewrite it to express it in a different form that could reveal potential asymptotes. Divide both sides of the equation by \( x^2 \) or \( y^2 \). We'll choose to divide by \( x^2 \), giving us \( y^2 = 9 + \frac{9y^2}{x^2} \). This shows how \( y^2 \) relates to \( x^2 \).
02
Consider Asymptotic Behavior as \( x \to \infty \)
Assume \( x \to \infty \), such that the term \( \frac{9y^2}{x^2} \to 0 \). The equation simplifies to \( y^2 = 9 \), giving us \( y = 3 \) or \( y = -3 \). These are horizontal asymptotes parallel to the \( x \)-axis.
03
Consider Asymptotic Behavior as \( y \to \infty \)
Assume \( y \to \infty \), requiring us to adjust the equation by dividing through by \( y^2 \) this time. Divide both sides of the equation by \( y^2 \), yielding \( x^2 = 9 + \frac{9x^2}{y^2} \). As \( \frac{9x^2}{y^2} \to 0 \), we get \( x^2 = 9 \), resulting in \( x = 3 \) or \( x = -3 \). These are vertical asymptotes parallel to the \( y \)-axis.
04
Review Asymptotes
Summarizing the results from the previous steps, we determine that the asymptotes of the function are \( y = 3 \), \( y = -3 \) (horizontal asymptotes), and \( x = 3 \), \( x = -3 \) (vertical asymptotes).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Horizontal Asymptotes
Horizontal asymptotes occur when the behavior of a function as the variable moves towards infinity can be captured as a straight line parallel to the x-axis. In our exercise, the original equation is rewritten in terms of \( y^2 \), as \( y^2 = 9 + \frac{9y^2}{x^2} \). As \( x \to \infty \), the term \( \frac{9y^2}{x^2} \) becomes negligibly small, approaching zero.
This simplifies the equation to \( y^2 = 9 \).
This simplifies the equation to \( y^2 = 9 \).
- This simplifies further to horizontal lines: \( y = 3 \) and \( y = -3 \).
- These lines depict where the curves of the function become more linear as \( x \) becomes extremely large.
Vertical Asymptotes
Vertical asymptotes highlight the behavior of a function as it approaches large values of the other variable, \( y \). When the original function is rewritten, this time in terms of \( x^2 \), we see \( x^2 = 9 + \frac{9x^2}{y^2} \). Assuming \( y \to \infty \), the part \( \frac{9x^2}{y^2} \) limits to zero.
This changes the equation to \( x^2 = 9 \).
This changes the equation to \( x^2 = 9 \).
- Consequently, we establish vertical lines: \( x = 3 \) and \( x = -3 \).
- These lines represent the paths towards which the curves approach.
Infinite Behavior
Infinite behavior in functions refers to how a function acts as input values become larger and larger, either positively or negatively. The process involves observing the changes as one variable reaches infinity, thereby simplifying parts of the equation.
- For horizontal asymptotes, as \( x \to \infty \), parts of the function become constant, depicting flatness or a level behavior, such as in \( y = 3 \) and \( y = -3 \).
- Vertical asymptotes, depicted through \( x = 3 \) and \( x = -3 \), show where the function steepens intensely.