Chapter 9: Problem 26
The exponential series \(1+\frac{x}{1 !}+\frac{x^{2}}{2 !}+\ldots+\frac{x^{n}}{n !}+\ldots\) on is absolutely convergent.
Short Answer
Expert verified
The series is absolutely convergent for all \( x \).
Step by step solution
01
Understand Absolute Convergence
The series is given as an exponential series which is a power series of the form \( \sum_{n=0}^{\infty} \frac{x^n}{n!} \). To determine if this series is absolutely convergent, we must check if the series \( \sum_{n=0}^{\infty} \left|\frac{x^n}{n!}\right| \) converges.
02
Simplify the Absolute Series
Because each term of the series is positive, the absolute series \( \sum_{n=0}^{\infty} \frac{x^n}{n!} \) is the same as the original series. Now consider \( \left|\frac{x^n}{n!}\right| = \frac{|x|^n}{n!} \), which are the terms of the modified series we need to analyze for convergence.
03
Apply the Ratio Test to Determine Convergence
Use the ratio test, which states that for a series \( \sum a_n \), the series converges absolutely if \( \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| < 1 \). Here, \( a_n = \frac{|x|^n}{n!} \). Compute the ratio \( \frac{a_{n+1}}{a_n} = \frac{|x|^{n+1}/(n+1)!}{|x|^n/n!} = \frac{|x|}{n+1} \).
04
Evaluate the Limit from the Ratio Test
Evaluate the limit \( \lim_{n \to \infty} \frac{|x|}{n+1} = 0 \). Since this limit is 0, which is less than 1, the ratio test confirms that the series \( \sum \frac{x^n}{n!} \) converges absolutely for all \( x \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponential Series
An exponential series is a special type of series, often related to the exponential function. It is expressed in the form \[1 + \frac{x}{1!} + \frac{x^2}{2!} + \cdots + \frac{x^n}{n!} + \cdots\]This series is very important in mathematics and is used to represent the exponential function \(e^x\). The beauty of this series is that it holds true for all real numbers \(x\), making it incredibly versatile. The expression "\(e^x\)" typically represents the sum of an infinite number of terms, each term increasing in degree from the previous one.
- The factorial, \(n!\), in the series is a key factor reducing the magnitude of each term as \(n\) increases. This contributes critically to the series' convergence.
- Each term in the series is positive when \(x\) is positive, allowing straightforward analysis of absolute convergence.
- This series is foundational in both calculus and many real-world applications, such as solving differential equations and modeling growth processes.
Ratio Test
The ratio test is an essential tool in determining the convergence of an infinite series. For a given series \[\sum a_n\] it involves checking the limit of the absolute value of the ratio of consecutive terms. The formal expression is \[\lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right|\]Conditions for convergence are:
- If the limit is less than 1, the series converges absolutely.
- If the limit is greater than 1 or infinite, the series diverges.
- If the limit equals 1, the test is inconclusive and further analysis is required.
- For \(a_n = \frac{|x|^n}{n!}\), consider the ratio \(\frac{a_{n+1}}{a_n} = \frac{|x|}{n+1}\).
- As \(n\) approaches infinity, \(\frac{|x|}{n+1}\) approaches 0, comfortably less than 1.
- This demonstrates the absolute convergence of the exponential series for all values of \(x\).
Power Series
A power series is a series of the form \[\sum_{n=0}^{\infty} c_n (x-a)^n\]where the \(c_n\) values are coefficients and \(a\) is the center of the series. This form resembles exponential series but is far more general. Power series can represent a wide variety of functions around a particular point, \(a\), within their radius of convergence.
- The power series converges within a certain interval, called the radius of convergence, centered at \(a\).
- For the exponential series, the center \(a\) is 0, and it converges everywhere on the real line, demonstrating infinite radius of convergence.
- Understanding convergence is crucial, as it tells us where a power series accurately represents a function.
- The exponential power series is a special case with all coefficients \(c_n = \frac{1}{n!}\), which leads to its absolute convergence everywhere.