Chapter 23: Problem 10
\(Z^{-1}\left\\{\frac{z}{(z+1)^{2}}\right\\}=\ldots \ldots\)
Short Answer
Expert verified
The Z-transform inverse is \( (n+1)(-1)^n u[n] \).
Step by step solution
01
Identify the Objective
We're tasked with finding the inverse Z-transform of the function \( F(z) = \frac{z}{(z+1)^2} \). This involves finding a time-domain sequence \( f[n] \) such that its Z-transform is equal to \( F(z) \).
02
Recognize the Z-Domain Structure
The given function \( F(z) = \frac{z}{(z+1)^2} \) suggests a form that may correspond to a derivative property in the time domain, particularly since the denominator involves a squared factor \((z+1)^2\).
03
Apply Z-Transform Derivative Property
Recall the property of Z-transforms: if \( F(z) = Z^{-1}\{f[n]\} \), then \( Z\{nf[n]\} = -z \frac{d}{dz}\{F(z)\} \). This means our \( F(z) \) might relate to a derivative of a known Z-transform.
04
Differentiate in Z-Domain
Let's differentiate \( F(z) = \frac{z}{(z+1)^2} \) with respect to \( z \):\[-\frac{d}{dz}\left(\frac{z}{(z+1)^2}\right) = \frac{2z}{(z+1)^3} - \frac{1}{(z+1)^2}\]This helps us rearrange the function into a sum suitable for recognizing the inverse transform.
05
Simplify and Identify Inverse Transform
Given that \( -\frac{d}{dz}\left( \frac{z}{(z+1)^2} \right) \) results in terms that match known inverse transforms, we note the standard transform pairs:- \( Z\{a^n u[n]\} = \frac{z}{z-a}\) for a step sequence.Thus, from our differentiation, the term corresponds to a first-order sequence with a step shift, \( \frac{2}{(z+1)^3} \) indicating a second sequence with step decay.
06
Translate to Time Domain Sequence
Using these observations, recognize that this derivative form leads us to the corresponding time-domain sequence:\[ f[n] = (n+1)(-1)^n u[n] \], where \( u[n] \) is the unit step function.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Z-Transform properties
The **Z-transform** is a powerful mathematical tool used in the analysis of discrete signals and systems. It plays a vital role in understanding how time-domain signals translate into the frequency domain. The transformative nature of the Z-transform can be summed up by its ability to map sequences into complex functions of a variable, typically denoted as \( z \). This transformation is useful for simplification of convolution operations, solving difference equations, and studying system behaviors in the frequency domain.
- The Z-transform is expressed as \( F(z) = \sum_{n=-\infty}^{\infty} f[n] z^{-n} \).
- It provides a comprehensive view by encompassing both the time domain and frequency domain characteristics.
- Its properties include linearity, time shifting, and convolution among others.
Time-domain sequences
In discrete signal processing, a **time-domain sequence** refers to a sequence of values or samples representing a signal in the time domain. This sequence provides information about how a signal changes over time. Analyzing these sequences is crucial for many applications, such as digital communications, image processing, and control systems.
- These sequences are often represented as \( f[n] \), where \( n \) is an integer representing discrete time intervals.
- A time-domain sequence can be viewed as a direct measurement of a signal or a processing result.
- Transformations like the Z-transform convert time-domain sequences into a frequency or complex domain for easier manipulation and analysis.
Derivative property in Z-domain
The **derivative property** in the Z-domain is a technique used to handle certain forms of Z-transforms where differentiation helps in recognizing patterns or simplifying functions. This property is particularly useful when dealing with transforms that involve additional polynomial structures, such as squared terms.
- The derivative property states: \( Z\{nf[n]\} = -z \frac{d}{dz}\{F(z)\} \).
- This property allows the translation of a difficult inverse Z-transform into a more identifiable form.
- It provides an analytical approach to deciphering complex functions by breaking them into simpler parts.
Unit step function
The **unit step function**, denoted as \( u[n] \), is a foundational concept in signal processing. It serves as a building block for more complex sequences and functions. This function is defined as 1 for all non-negative integers \( n \) and 0 for negative \( n \), essentially "turning on" at \( n = 0 \).
- The unit step is particularly useful in defining sequences that begin at a certain point.
- In the Z-domain, it often aids in indicating the presence and start of sequences, providing clear boundaries.
- Its inclusion in expressions corresponds to sequences with defined initiation points, making it essential for modeling real-world signals.