Chapter 7: Problem 2
Let \(A=\left[\begin{array}{cc}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta\end{array}\right] .\) Find the eigenvectors of \(A\) for the two cases (a) \(\theta\) is a multiple of \(\pi\); (b) \(\theta\) is not a multiple of \(\pi\).
Short Answer
Expert verified
For (a), eigenvectors are real: align along or opposite to coordinate axes. For (b), eigenvectors are complex due to complex eigenvalues.
Step by step solution
01
Understand the Structure of A
The matrix \( A \) is a rotation matrix that rotates vectors in 2D space by an angle \( \theta \). The entries are \( \cos \theta, -\sin \theta, \sin \theta, \cos \theta \), representing the typical structure of a rotation matrix.
02
Eigenvalues of Matrix A
The eigenvalues \( \lambda \) of a matrix \( A \) are obtained by solving the characteristic equation \( \det(A - \lambda I) = 0 \), where \( I \) is the identity matrix. For matrix \( A \), we have: \[A - \lambda I = \begin{pmatrix} \cos \theta - \lambda & -\sin \theta \ \sin \theta & \cos \theta - \lambda \end{pmatrix}\]Then, compute the determinant: \[\det(A - \lambda I) = (\cos \theta - \lambda)^2 + \sin^2 \theta \]Setting this to zero results in: \[\lambda^2 - 2\lambda \cos \theta + 1 = 0\]
03
Solving the Characteristic Equation
The characteristic equation \( \lambda^2 - 2\lambda \cos \theta + 1 = 0 \) is a quadratic equation, and its solutions can be found using the quadratic formula: \[ \lambda = \frac{2\cos \theta \pm \sqrt{(2\cos \theta)^2 - 4}}{2} \] Simplifying gives the eigenvalues: \[ \lambda = \cos \theta \pm i \sin \theta \], which can be written as \( e^{i\theta} \) and \( e^{-i\theta} \) since \( \cos \theta \pm i \sin \theta \) are expressions for complex exponentials.
04
Case (a) \(\theta\) is a Multiple of \(\pi\)
When \( \theta \) is a multiple of \( \pi \), \( \cos \theta = \pm 1 \) and \( \sin \theta = 0 \). In this case, the eigenvalues simplify to real numbers, either \( +1 \) or \( -1 \). For \( \lambda = 1 \), the eigenvector solves \( (A - I)\mathbf{v} = 0 \), leading to vectors along \( x \)-axis or \( x = y \). For \( \lambda = -1 \), solve \( (A + I)\mathbf{v} = 0 \), resulting in vectors along \( x = -y \).
05
Case (b) \(\theta\) is not a Multiple of \(\pi\)
For non-multiples of \( \pi \), eigenvalues are complex, \( \cos \theta + i\sin \theta = e^{i\theta} \) and its complex conjugate \( e^{-i\theta} \). Eigenvectors corresponding to these eigenvalues are complex and found by solving \( (A - \lambda I)\mathbf{v} = 0 \) for each \( \lambda \). The eigenvectors involve solving equations involving complex numbers, and typically do not align with coordinate axes directly.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Rotation Matrix
A rotation matrix is a special type of square matrix used to rotate vectors in a plane. It has a defined structure that maintains vector lengths and angles during rotation. Specifically for a 2D plane, the rotation matrix for rotating a vector by an angle \( \theta \) is described by:
- \( \cos \theta \) in the top-left and bottom-right positions
- \( -\sin \theta \) in the top-right position
- \( \sin \theta \) in the bottom-left position
Characteristic Equation
The characteristic equation is critical for finding eigenvalues of a matrix. For any matrix \( A \), you form the characteristic equation by calculating the determinant of \( A - \lambda I \), where \( I \) is the identity matrix and \( \lambda \) are the eigenvalues. This gives us the equation \( \det(A - \lambda I) = 0 \).
This simplifies to a polynomial equation in terms of \( \lambda \). Solving this polynomial equation yields the eigenvalues.
For the rotation matrix \( A \), its characteristic equation is derived as follows:
This simplifies to a polynomial equation in terms of \( \lambda \). Solving this polynomial equation yields the eigenvalues.
For the rotation matrix \( A \), its characteristic equation is derived as follows:
- Subtract \( \lambda I \) from \( A \) which results in \( \begin{pmatrix} \cos \theta - \lambda & -\sin \theta \ \sin \theta & \cos \theta - \lambda \end{pmatrix} \)
- The determinant is calculated as \( (\cos \theta - \lambda)^2 + \sin^2 \theta \)
- Setting the determinant equal to zero provides the characteristic equation: \( \lambda^2 - 2\lambda \cos \theta + 1 = 0 \)
Complex Eigenvalues
When dealing with matrices like the rotation matrix, complex eigenvalues often emerge. Especially for the rotation matrix \( A \), when \( \theta \) is not a multiple of \( \pi \), the eigenvalues are complex. Specifically, they are given by:
To find the corresponding eigenvectors, solve \( (A - \lambda I)\mathbf{v} = 0 \) in the complex number system. This can be tricky, as complex eigenvectors don't align with real axis-oriented vectors and are instead vital in systems modeled by wave functions or in quantum mechanics. The presence of complex eigenvalues in a rotation matrix reflects the sustained rotational effect it imposes on vectors.
- \( \lambda = \cos \theta + i \sin \theta \)
- \( \lambda = \cos \theta - i \sin \theta \)
To find the corresponding eigenvectors, solve \( (A - \lambda I)\mathbf{v} = 0 \) in the complex number system. This can be tricky, as complex eigenvectors don't align with real axis-oriented vectors and are instead vital in systems modeled by wave functions or in quantum mechanics. The presence of complex eigenvalues in a rotation matrix reflects the sustained rotational effect it imposes on vectors.