Chapter 6: Problem 1
For each of the following linear transformations \(T\), find im \(T\) and ker \(T\). (a) \(T: \mathbb{R}^{2} \rightarrow \mathbb{R}^{2}\) given by \(T((x, y))=(x+y, 0) ;\) (b) \(T: \mathbb{R}^{2} \rightarrow \mathbb{R}^{2}\) given by \(T((x, y))=(x+y, x-y)\); (c) \(T: \mathbb{R}^{3} \rightarrow \mathbb{R}^{3}\) given by \(T((x, y, z))=(x, y, y)\) (d) \(T: \mathbb{R}^{3} \rightarrow \mathbb{R}^{3}\) given by \(T((x, y, z))=(2 x-y+z,-x+3 y+5 z, 10 x-9 y-7 z)\) (e) \(T: M_{2,2} \rightarrow \mathbb{R}^{3}\) given by \(T\left(\left[\begin{array}{ll}a & b \\ c & d\end{array}\right]\right)=(a+b-c, b+d, a-c-d)\) (f) \(T: P_{2} \rightarrow P_{2}\) given by \(T\left(a_{0}+a_{1} x+a_{2} x^{2}\right)=a_{1}+2 a_{2} x\).
Short Answer
Step by step solution
Understanding Transformation (a)
Kernel of T (a)
Image of T (a)
Understanding Transformation (b)
Kernel of T (b)
Image of T (b)
Understanding Transformation (c)
Kernel of T (c)
Image of T (c)
Understanding Transformation (d)
Kernel of T (d)
Image of T (d)
Understanding Transformation (e)
Kernel of T (e)
Image of T (e)
Understanding Transformation (f)
Kernel of T (f)
Image of T (f)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Kernel of a Transformation
- \( \ker T = \{ \mathbf{v} \in V \ | \ T(\mathbf{v}) = \mathbf{0} \} \) \
For example, if given \( T((x, y)) = (x+y, 0) \), we find the kernel by setting \( (x+y, 0) = (0, 0) \), ultimately revealing that \( x+y=0 \). Thus, the kernel is spanned by vectors of the form \((-1, 1)\). In other words, any vector on the line \( x+y=0 \) forms the kernel.
The kernel offers insight into how a transformation compresses or reduces dimensionality, as it encompasses vectors mapped to zero. It's a powerful tool to understand when and why certain mappings send elements to trivial results.
Image of a Transformation
- \( \text{im} \, T = \{ \mathbf{w} \in W \ | \ \exists \mathbf{v} \in V, \text{ such that } T(\mathbf{v}) = \mathbf{w} \} \)
Take, for instance, the transformation \( T((x, y)) = (x+y, x-y) \). To find its image, observe that any vector of form \((a, b)\) in \( \mathbb{R}^2 \) can be formed. Specifically, \( (1, 1) \) and \( (1, -1) \) serve as a basis for the range, fully spanning \( \mathbb{R}^2 \).
The image provides critical understanding of the transformation's behavior over an input space, indicating whether it fully covers the output space or is constrained to a subspace.
Basis of a Vector Space
- Linearly independent means no vector in the set can be written as a linear combination of the others.
- To span \( V \), every vector in \( V \) can be expressed as a linear combination of the basis vectors.
Consider a transformation \( T: \mathbb{R}^3 \rightarrow \mathbb{R}^3 \) like \( T((x, y, z)) = (x, y, y) \). The image of this transformation is spanned by the vectors \((1, 0, 0)\) and \((0, 1, 1)\), making these vectors a basis for the image. The kernel, on the other hand, is for vectors of form \((0, 0, z)\), with a basis provided by \((0, 0, 1)\).
Understanding the basis of a space is vital as it reveals the intrinsic dimensional characteristics of transformations, confirming which spaces they transform to or from efficiently.