Chapter 6: Problem 41
REVIEW If the equation below has no real solutions, then which of the following could not be the value of \(a ?\) \(a x^{2}-6 x+2=0\) \(\mathbf{F}^{3}\) \(G 4\) \(\mathbf{H}^{5}\) 6
Short Answer
Expert verified
The value of \(a\) that cannot be chosen is 4.
Step by step solution
01
Recognize the Form of the Equation
The given equation is a quadratic equation in the form \( ax^2 - 6x + 2 = 0 \). This type of equation is represented as \( ax^2 + bx + c = 0 \), where \( a, b, \) and \( c \) are constants. Here, \( a \) is the coefficient we want to find that makes the equation have no real solutions.
02
Use the Discriminant
The discriminant \( \Delta \) of a quadratic equation \( ax^2 + bx + c = 0 \) is given by \( b^2 - 4ac \). If \( \Delta < 0 \), the equation has no real solutions. We substitute \( a \), \( b = -6 \), and \( c = 2 \) into the discriminant formula: \( (-6)^2 - 4(a)(2) \).
03
Set Up the Discriminant Inequality
For the quadratic equation to have no real solutions, we need the discriminant \( \Delta < 0 \). This gives us the inequality: \((-6)^2 - 8a < 0\).
04
Solve the Inequality
Simplify the inequality: \(36 - 8a < 0\) leads to \(36 < 8a\). Dividing both sides by 8, we have \( a > \frac{36}{8} \), simplifying further to \( a > 4.5 \).
05
Analyze the Choices
From the inequality \( a > 4.5 \), any \( a \) value less than or equal to 4.5 will not satisfy the condition for no real solutions. The options are 3, 4, 5, and 6. Since 4 is less than 4.5, it would not satisfy the condition, hence it cannot make the equation have no real solutions.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Discriminant
The discriminant is a crucial tool when dealing with quadratic equations. It helps us determine the nature of the roots, or solutions, for these equations. In a quadratic equation, which is typically in the form \(ax^2 + bx + c = 0\), the discriminant \(\Delta\) is represented by the formula \(b^2 - 4ac\). This value can tell us a lot about the solutions:
- When \(\Delta > 0\), the quadratic equation has two distinct real solutions.
- When \(\Delta = 0\), there is exactly one real solution, sometimes referred to as a repeated or double root.
- When \(\Delta < 0\), the quadratic equation has no real solutions but instead has two complex solutions.
Finding Real Solutions
Real solutions of a quadratic equation occur when we substitute the coefficients \(a, b, \) and \(c\) into the quadratic formula. However, the discriminant plays a pivotal role as it indicates the reality of these solutions before any further calculation.When discussing real solutions, they can be geometrically visualized as the points where the parabola intersects the x-axis in a graph. If a quadratic equation has two real solutions, it means the parabola touches the x-axis at two points. Conversely, one real solution means the vertex of the parabola just touches the x-axis.In our exercise, we want to find the values of \(a\) that result in no real solutions. We use the condition \(\Delta < 0\), ensuring that the parabola stays above or below the x-axis without crossing it.
Working with Inequalities
Inequalities are essential when determining the conditions for the discriminant. To explore when a quadratic equation has no real solutions, we set up an inequality. Given a quadratic equation like \(ax^2 - 6x + 2 = 0\), we calculate using the discriminant \((-6)^2 - 4(a)(2) < 0\).Our simplified inequality is \(36 - 8a < 0\). Solving this inequality involves isolating \(a\) to find the interval where the statement holds true:
- Subtract 36 from both sides: \(-8a < -36\).
- Divide by -8, remembering to reverse the inequality sign, leading to \(a > 4.5\).