Chapter 5: Problem 55
Two vertices of \(\triangle A B C\) are \(A(3,8)\) and \(B(9,12) . A D\) is a median with \(D\) at \((12,3).\) The graph of point \(E\) is at \((6,6) . \overline{E F}\) intersects \(\overline{B D}\) at \(F .\) If \(F\) is at \(\left(10 \frac{1}{2}, 7 \frac{1}{2}\right),\) is \(\overline{E F}\) a perpendicular bisector of \(\overline{B D ?}\) Explain.
Short Answer
Step by step solution
Calculate the Midpoint of BD
Calculate the Slope of BD
Calculate the Slope of EF
Check Perpendicularity
Confirmation as a Perpendicular Bisector
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Midpoint formula
- Calculate \(x\) with \(\frac{9 + 12}{2}\), which results in \(10.5\).
- Calculate \(y\) with \(\frac{12 + 3}{2}\), yielding \(7.5\).
Slope calculation
- \( m = \frac{y_2 - y_1}{x_2 - x_1} \)
- Subtract the y-coordinates: \(3 - 12 = -9\).
- Subtract the x-coordinates: \(12 - 9 = 3\).
- Calculate the slope: \(\frac{-9}{3} = -3\).
Perpendicular bisector
- \(\overline{EF}\) must pass through the midpoint of \(\overline{BD}\).
- The lines \(\overline{EF}\) and \(\overline{BD}\) should be perpendicular, which means their slopes' product should be \(-1\).
- Point \(F\), matching the midpoint \((10.5, 7.5)\), confirms the first condition.
- The slope of \(\overline{BD}\) is \(-3\) and for \(\overline{EF}\), it is \(\frac{1}{3}\).
- Their slopes' product: \(-3 \times \frac{1}{3} = -1\).
Coordinate geometry
- Points are defined through coordinates \((x, y)\).
- Lines are explored using equations and slopes.
- Midpoints and bisectors are identified using formulas.