Chapter 4: Problem 33
The total distance from Charlotte to Raleigh to Winston-Salem and back to Charlotte is about 292 miles. The distance from Charlotte to Winston-Salem is 22 miles less than the distance from Raleigh to Winston-Salem. The distance from Charlotte to Raleigh is 60 miles greater than the distance from Winston- Salem to Charlotte. Classify the triangle that connects Charlotte, Raleigh, and Winston-Salem. (IMAGE CAN'T COPY)
Short Answer
Step by step solution
Define Variables
Establish Relationships
Use Total Distance
Substitute and Solve
Solve for \( d_2 \)
Determine \( d_1 \) and \( d_3 \)
Classify the Triangle
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Triangle Classification
- **Equilateral Triangle**: All sides are equal in length, and all angles are equal, typically measuring 60 degrees each.
- **Isosceles Triangle**: Two sides are equal in length, which also means two of its angles are equal.
- **Scalene Triangle**: All sides are different in length, and consequently, all angles are also different.
Additionally, triangles can also be classified by their angles:
- **Acute Triangle**: All angles are less than 90 degrees.
- **Right Triangle**: One angle is exactly 90 degrees.
- **Obtuse Triangle**: One angle is greater than 90 degrees.
Distance Calculation
- \( d_1 \): The distance from Charlotte to Winston-Salem
- \( d_2 \): The distance from Winston-Salem to Raleigh
- \( d_3 \): The distance from Raleigh to Charlotte
- \( d_1 = d_2 - 22 \) which means "the distance from Charlotte to Winston-Salem is 22 miles less than the distance from Raleigh to Winston-Salem."
- \( d_3 = d_1 + 60 \) which implies that "the distance from Charlotte to Raleigh is 60 miles greater than the distance from Winston-Salem to Charlotte."
By using the known total distance (292 miles), which means the sum of all three distances equals this amount, we set up the equation \( d_1 + d_2 + d_3 = 292 \). Substituting the expressions for \( d_1 \) and \( d_3 \) allows us to find each specific distance.
Equation Solving
\[(d_2 - 22) + d_2 + (d_2 + 38) = 292\]
simplifies into the linear equation
\[3d_2 + 16 = 292\].
This step requires simplifying by first combining like terms, then subtracting 16 from both sides to isolate the term with \(d_2\). This results in the equation
\[3d_2 = 276\].
Solving for \(d_2\) is performed by dividing each side by 3, yielding
\[d_2 = 92\] miles.
After determining \(d_2\), we substitute back to discover \(d_1 = 70\) miles and \(d_3 = 130\) miles. This step-by-step equation solving showcases the logical process in tackling distance calculations, leading us to effectively classify the triangle.