Chapter 11: Problem 18
COORDINATE GEOMETRY Find the area of trapezoid \(P Q R T\) given the coordinates of the vertices. $$P(0,3), Q(3,1), R(2,-7), T(-7,-1)$$
Short Answer
Expert verified
The area of trapezoid \(PQRT\) is 52 square units.
Step by step solution
01
Identify Trapezoid Bases
To find the area of a trapezoid, we need to identify the two parallel sides which act as bases. A common method is to determine horizontal lines by checking which coordinates share the same y-values. However, in this case, we'll proceed with calculating the sides since the points seem arbitrary.
02
Calculate Length of PQ
Use the distance formula for the length of side \(PQ\).\[ PQ = \sqrt{(3-0)^2 + (1-3)^2} = \sqrt{3^2 + (-2)^2} = \sqrt{13} \]
03
Calculate Length of RT
Use the distance formula for the length of side \(RT\).\[ RT = \sqrt{(2 - (-7))^2 + (-7 - (-1))^2} = \sqrt{(9)^2 + (-6)^2} = \sqrt{117} \]
04
Verify Perpendicular Bases
To confirm that \(PQ\) and \(RT\) are parallel, verify they are not parallel by comparing gradients. Calculate the gradient of both lines and observe neither offers a unity negative ratio, indicating the requirement of no parallelism.
05
Set Coordinates in Shoelace Formula
Plug coordinates into the shoelace (or surveyor's) formula to find the area. Arrange as follows: \(P(0,3), Q(3,1), R(2,-7), T(-7,-1)\) and repeat. Calculate: \[\frac{1}{2}\left|(0 \times 1 + 3 \times -7 + 2 \times -1 + (-7) \times 3) - (3 \times 3 + 1 \times 2 + -7 \times -7 + -1 \times 0)\right|\]
06
Compute Shoelace Formula
Carrying out the calculations, \[\frac{1}{2}\left|(0 + -21 + -2 + -21) - (9 + 2 + 49 + 0)\right| = \frac{1}{2}\left|-44 - 60\right| = \frac{1}{2}(104) = 52\] The area of trapezoid \(PQRT\) is 52 square units.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Trapezoid Area
A trapezoid is a quadrilateral with at least one pair of parallel sides. The formula for the area of a trapezoid is particularly known for its simplicity when the bases and height are clearly defined. In coordinate geometry, however, the process can be a bit tricky as it requires a bit more calculation. To find the area of a trapezoid when given its vertices in a coordinate plane, we can use the coordinates directly to our advantage.
To start with, remember that the area of a trapezoid is given by the formula:
To start with, remember that the area of a trapezoid is given by the formula:
- Area = \( \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{Height} \)
Distance Formula
The distance formula is invaluable in coordinate geometry, primarily when calculating the length of a line segment between two points. This formula is essentially derived from the Pythagorean theorem and provides a way to calculate how far apart points in a plane are from each other.
For any two points, \( A(x_1, y_1) \) and \( B(x_2, y_2) \), the distance between these points is given by:
For any two points, \( A(x_1, y_1) \) and \( B(x_2, y_2) \), the distance between these points is given by:
- \( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \)
Shoelace Formula
The shoelace formula, also known as Gauss's area formula, is a very efficient linear algebra-based algorithm for calculating the area of a simple polygon when the vertices are known and given in a specific order. This method is especially useful for polygons when determining areas using traditional base-height measurements is impractical.
The shoelace formula is applied by arranging the vertices in order, calculating specific cross-products, and applying them in the formula:
The shoelace formula is applied by arranging the vertices in order, calculating specific cross-products, and applying them in the formula:
- \[ \text{Area} = \frac{1}{2} \left| x_1y_2 + x_2y_3 + ... + x_ny_1 - (y_1x_2 + y_2x_3 + ... + y_nx_1) \right| \]