Chapter 5: Problem 2
Gib eine spezielle Lösung der erzwungenen gedämpften Schwingung an, die durch eine periodische äußere Kraft der Form \(b \sin (\Omega t)\) mit \(b \in \mathbb{R}\) und \(\Omega \in \mathbb{R}_{+}^{*}\) erzeugt wird, ermittle also eine Lösung der Differenzialgleichung $$ \ddot{x}(t)+2 \mu \dot{x}(t)+\omega_{0}^{2} x(t)=b \sin (\Omega t) $$
Short Answer
Step by step solution
Identify the Homogeneous Solution
Analyze Damping Conditions
Write the Homogeneous Solution
Propose a Particular Solution
Substitute into the Equation
Solve for Coefficients A and B
Write the General Solution
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Damped Harmonic Motion
When analyzing damped harmonic motions mathematically, we often use a differential equation. This equation typically has the form:
- \( \ddot{x}(t) + 2\mu \dot{x}(t) + \omega_{0}^{2} x(t) = 0 \)
Depending on the relationship between \( \mu \) and \( \omega_0 \), the system can exhibit different types of damping:
- Underdamped: \( \mu^2 < \omega_0^2 \), where oscillations gradually decrease over time.
- Critically Damped: \( \mu^2 = \omega_0^2 \), where the system returns to equilibrium as fast as possible without oscillating.
- Overdamped: \( \mu^2 > \omega_0^2 \), where the system returns to equilibrium without oscillating and slower than critical damping.
Particular Solution
- \( x_p(t) = A \sin(\Omega t) + B \cos(\Omega t) \)
In this solved example, after comparison, we find that typically \( B = 0 \), aligning with the nature of the forcing term being purely sine. The value of \( A \) is then calculated with:
- \( A = \frac{b}{\omega_0^2 - \Omega^2 + 2i\mu\Omega} \)
Homogeneous Solution
- \( \ddot{x}(t) + 2\mu \dot{x}(t) + \omega_{0}^{2} x(t) = 0 \)
- \( r^2 + 2\mu r + \omega_{0}^{2} = 0 \)
- \( r = -\mu \pm i\sqrt{\omega_{0}^{2} - \mu^{2}} \)
- \( x_h(t) = e^{-\mu t} (C_1 \cos(\omega_d t) + C_2 \sin(\omega_d t)) \)