Chapter 2: Problem 4
Find all solutions to the quadratic equation \(z^{2}+i z-(2+6 i)=0\).
Short Answer
Expert verified
The solutions are \( \frac{3}{2} + \frac{3i}{2} \) and \( \frac{-3}{2} - \frac{5i}{2} \).
Step by step solution
01
- Identify the coefficients
In the quadratic equation \[ z^2 + iz - (2 + 6i) = 0 \] identify the coefficients. Here, the coefficient of \( z^2 \) is \( a = 1 \), the coefficient of \( z \) is \( b = i \), and the constant term is \( c = -(2 + 6i) \).
02
- Use the quadratic formula
The quadratic formula is given by \[ z = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]. Plugging in the coefficients identified: \( a = 1 \), \( b = i \), and \( c = -(2 + 6i) \), we get \[ z = \frac{-i \pm \sqrt{i^2 - 4 \cdot 1 \cdot (-2 - 6i)}}{2 \cdot 1} \].
03
- Calculate the discriminant
Calculate the discriminant: \[ i^2 - 4 \cdot 1 \cdot (-2 - 6i) \]. Notice that \( i^2 = -1 \). Thus, \[ i^2 = -1 \] and \[ -4(-2 - 6i) = 8 + 24i \]. Therefore, the discriminant is \[ -1 + 8 + 24i = 7 + 24i \].
04
- Simplify the square root of the discriminant
Simplify \( \sqrt{7 + 24i} \). To find \( \sqrt{7 + 24i} \), represent it in polar form \( re^{i\theta} \). The modulus is \[ r = \sqrt{7^2 + 24^2} = 25 \]. The argument is \[ \theta = \tan^{-1}\left(\frac{24}{7}\right) \approx \tan^{-1}(3.4286) \]. Hence, \( \sqrt{7 + 24i} = \sqrt{25} e^{i \theta/2} = 5 e^{i \theta/2} \). Therefore, \( \sqrt{7 + 24i} = 5(cos(\theta/2) + i sin(\theta/2)) \). Calculate it: \[ \sqrt{7 + 24i} \approx 3 + 4i \] for practical use.
05
- Solve for z
Substitute back into the quadratic formula: \[ z = \frac{-i \pm (3 + 4i)}{2} \]. Thus, solve for two values: \[ z_1 = \frac{-i + 3 + 4i}{2} = \frac{3 + 3i}{2} = \frac{3}{2} + \frac{3i}{2} \] and \[ z_2 = \frac{-i - 3 - 4i}{2} = \frac{-3 - 5i}{2} = \frac{-3}{2} - \frac{5i}{2} \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool for solving quadratic equations. A quadratic equation is generally written as \( ax^2 + bx + c = 0 \).
The quadratic formula helps you find the solutions to this equation, referred to as the roots.
It is given by:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \].
The expression inside the square root, \( b^2 - 4ac \), is called the discriminant, and it determines the nature of the roots.
The plus-minus symbol (\pm) indicates that there are usually two solutions: one for the plus and one for the minus.
The quadratic formula helps you find the solutions to this equation, referred to as the roots.
It is given by:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \].
The expression inside the square root, \( b^2 - 4ac \), is called the discriminant, and it determines the nature of the roots.
The plus-minus symbol (\pm) indicates that there are usually two solutions: one for the plus and one for the minus.
Complex Numbers
Complex numbers extend the familiar real number system.
They are written in the form \( z = x + yi \), where \( x \) and \( y \) are real numbers, and \( i \) is the imaginary unit, which satisfies \( i^2 = -1 \).
This means complex numbers have both a real part (x) and an imaginary part (y).
For example, in the quadratic equation \( z^2 + iz - (2 + 6i) = 0 \), the solutions are found in the set of complex numbers.
They are written in the form \( z = x + yi \), where \( x \) and \( y \) are real numbers, and \( i \) is the imaginary unit, which satisfies \( i^2 = -1 \).
This means complex numbers have both a real part (x) and an imaginary part (y).
For example, in the quadratic equation \( z^2 + iz - (2 + 6i) = 0 \), the solutions are found in the set of complex numbers.
Discriminant
The discriminant is an essential part of the quadratic formula.
It is the term under the square root: \( b^2 - 4ac \).
The value of the discriminant tells us about the nature of the roots:
It is the term under the square root: \( b^2 - 4ac \).
The value of the discriminant tells us about the nature of the roots:
- If the discriminant is positive, there are two distinct real roots.
- If the discriminant is zero, there is one real root (a repeating root).
- If the discriminant is negative, the roots are complex conjugates, meaning they are not real numbers.
Polar Form of Complex Numbers
To simplify the square root of a complex number like
\( \sqrt{7 + 24i} \), we use polar form.
A complex number can be represented as
\( re^{i\theta} \), where \( r \) is the modulus and \( \theta \) is the argument.
The modulus \( r \) is the distance from the origin in the complex plane and is calculated as \[ r = \sqrt{x^2 + y^2} \].
In our example, \( r = \sqrt{7^2 + 24^2} = 25 \).
The argument \( \theta \) is the angle with the positive real axis and is found using \[ \theta = \tan^{-1} \left( \frac{y}{x} \right) \].
Once we have \( r \) and \( \theta \), we can find the square root:
\( \sqrt{re^{i\theta}} = \sqrt{r} \cdot e^{i \theta / 2} \). In our equation, this becomes \( \sqrt{7 + 24i} \approx 3 + 4i \).
This makes it easier to continue solving the quadratic equation.
\( \sqrt{7 + 24i} \), we use polar form.
A complex number can be represented as
\( re^{i\theta} \), where \( r \) is the modulus and \( \theta \) is the argument.
The modulus \( r \) is the distance from the origin in the complex plane and is calculated as \[ r = \sqrt{x^2 + y^2} \].
In our example, \( r = \sqrt{7^2 + 24^2} = 25 \).
The argument \( \theta \) is the angle with the positive real axis and is found using \[ \theta = \tan^{-1} \left( \frac{y}{x} \right) \].
Once we have \( r \) and \( \theta \), we can find the square root:
\( \sqrt{re^{i\theta}} = \sqrt{r} \cdot e^{i \theta / 2} \). In our equation, this becomes \( \sqrt{7 + 24i} \approx 3 + 4i \).
This makes it easier to continue solving the quadratic equation.