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Prove Theorem 5-14 for one diagonal of the rhombus, (Note that a proof for the other would be similar, step-by-step).

Short Answer

Expert verified

Theorem 5-14 is proved by the definition of a rhombus, SSS postulate, parts of the congruent triangle are congruent, the definition of an angle bisector, the definition of a rhombus.

Step by step solution

01

Step 1. State the theorem 5-14.

The theorem is:

For one diagonal of a rhombus bisects two angles of the rhombus.

Prove, RT¯bisects ∠QRSand ∠QTS.

And prove QS¯bisects ∠TQRand ∠TSR.

02

Step 2. State the proof.

The given statement can be proved as below:

Statement

Reasons

Rhombus QRST,

QS¯ and RT¯ are diagonals

Given.

QR¯≅QT¯≅TS¯≅SR¯

Definition of a rhombus.

In ΔQRS and ΔQTS,

QR¯≅QT¯, RS¯≅TS¯and QS¯≅QS¯

Proved above.

ΔQRS≅ΔQTS.

SSS postulate.

∠TQS≅∠RQS, ∠TSQ≅∠TSR

Definition of an angle bisector.

QR¯≅QT¯≅TS¯≅SR¯

Definition of a rhombus.

In ΔTQRand ΔTSR,

TQ¯≅TS¯, QR¯≅RS¯ and TR¯≅TR¯.

Proved above.

ΔTQR≅ΔTSR.

SSS postulate.

∠QTR≅∠STR, ∠QRT≅∠SRT

Parts of congruent triangle are congruent.

RT¯bisects ∠QRSand ∠QTS

Definition of an angle bisector.

03

Step 3. State the conclusion.

Therefore, Theorem 5-14 is proved by definition of a rhombus, SSS postulate, parts of the congruent triangle are congruent, the definition of an angle bisector, definition of a rhombus.

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