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91Ó°ÊÓ

Given: Rectangle QRST; â–±RKST; â–±JQST

Prove: JT¯≅KS¯.

Short Answer

Expert verified

JT¯≅KS¯

Step by step solution

01

Step 1. State the concept used.

Diagonals of rectangles are equal and bisect each other.

The opposite sides of a parallelogram are equal.

02

Step 2. State the proof.

Construct a rectangle QRSTand parallelogram â–±RKSTwith parallelogram â–±JQST.

In parallelogram â–±RKST, RTand SKare opposite sides which are parallel,

Therefore, RT¯≅SK¯

Similarly, in parallelogram â–±JQST, JTand QSare opposite sides which are parallel,

Therefore, JT¯≅QS¯.

Now, in rectangle QRST, TRand QSare diagonal of the rectangle and as the diagonal of the rectangle are equal to each other, it can be said that, TR¯≅QS¯.

From the above three relations by the property of transitivity of congruence, JT¯≅KS¯.

Hence, JT¯≅KS¯.

03

Step 3. State the conclusion.

Therefore, JT¯≅KS¯(proved).

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