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Given: ▱ABZY; ZY¯≅BX¯; ∠1≅∠2

Prove: ABZY is a rhombus.

Short Answer

Expert verified

The two-column proof of ABZYis a rhombus is:

Statement

Reason

ZY¯≅BX¯

Given.

∠1≅∠2

Given.

∠AXB≅∠YXZ

Vertical angles are congruent.

ΔAXB≅ΔYXZ

AAS.

AX≅XZ

CPCTC.

BX≅XY

CPCTC.

Hence ∠YABis a right angle.

Definition of a parallelogram.

AZ¯is perpendicular bisector to BY¯and BY¯ is perpendicular bisector to AZ¯.

Definition of perpendicular bisector.

ABZYis a rhombus.

Definition of a rhombus.

Step by step solution

01

Step 1. Consider the diagram.

Parallelogram ABZYis:

Here, ZY¯≅BX¯and ∠1≅∠2.

02

Step 2. State the proof.

Statement

Reason

ZY¯≅BX¯

Given.

∠1≅∠2

Given.

∠AXB≅∠YXZ

Vertical angles are congruent.

ΔAXB≅ΔYXZ

AAS.

AX≅XZ

CPCTC.

BX≅XY

CPCTC.

Hence ∠YABis a right angle.

Definition of a parallelogram.

AZ¯is perpendicular bisector to BY¯and BY¯ is perpendicular bisector to AZ¯.

Definition of perpendicular bisector.

ABZYis a rhombus.

Definition of a rhombus.

03

Step 3. State the conclusion.

Therefore, ABZYis a rhombus.

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